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aleksley [76]
3 years ago
14

A recursive definition is a definition:____.

Computers and Technology
1 answer:
saveliy_v [14]3 years ago
6 0
The correct answer is D
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brielle is researching substitution ciphers. she came across a cipher in which the entire alphabet was rotated 13 steps. what ty
kogti [31]

Caesar cipher is a very common type of substitution cipher where each letter in the plaintext is moved or shifted to a known number of places down the alphabet.

The type of cipher is this is ROT13

  • ROT13ROT13 is a simple letter substitution cipher. It functions by the replacement of a letter with the 13th letter after it in the alphabet. It is commonly known as Caesar cipher used in ancient Rome

Conclusively we can say that ROT13 is a commonly known Caesar cipher that replaces a letter with the 13th letter after it in the alphabet.

Learn more from

brainly.com/question/15300028

3 0
3 years ago
A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca
natima [27]

Answer:

There are 5,598,527,220 ways to choose <em>5</em> cards of type 1, <em>4 </em>cards<em> </em>of type 2, <em>2</em> cards of type 3 and <em>2</em> cards of type 4 from a set of 13 cards.

Explanation:

The <em>crucial point</em> of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of <em>combination</em> since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for <em>combinations</em> is \\ \frac{n!}{(n-k)!k!}, where <em>n</em> is the total of elements available and <em>k </em>is the size of a selection of <em>k</em> elements  from which we can choose from the total <em>n</em>.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287, since \\ \frac{8!}{8!} = 1.

Choosing 4 cards of type 2 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715, since \\ \frac{9!}{9!} = 1.

Choosing 2 cards of type 3 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78, since \\ \frac{11!}{11!}=1.

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78.

We still need to make use of the <em>Multiplication Principle</em> to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the <em>multiplication</em> of all them.

5 0
4 years ago
Why do companies send updates to devices
Luden [163]
To ensure that they are up to date and running smoother than before. Withought updates our devices wouldnt work properly the way they are supposed to!
3 0
4 years ago
You have received a "no boot device found" notification upon booting your system. what does this mean, and what can you do to tr
zloy xaker [14]
Basically no boot device could be 1 of three things listed below.

1. You have connected an incorrect external device and the system responds to boot from this however no operating system is available. Hence the error. What to do : You have disconnect, reset and select the correct bootable device.
2. You have a faulty hardware specifically your bootable harddisk, corrupted or malfunctioning. You have to reformat and correct the bios installed on the disk.
3. You have not selected correct bootable device. - Select the correct harddisk, if you have partition, be sure to select the one with the Operating system is installed to.
8 0
3 years ago
What are the required components of a database function? ​
vagabundo [1.1K]

Answer:

Following are the required components of a database function :-

  • Software
  • Data
  • Hardware
  • Procedures
  • Data Manager
  • Database Access language
  • Query processor

hope it helps!

5 0
3 years ago
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