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babymother [125]
3 years ago
10

Who are the following furries?

Computers and Technology
2 answers:
Mandarinka [93]3 years ago
8 0

Answer:   ok

Explanation:

Len [333]3 years ago
6 0

Answer:

WHY DO YOU KNOW SO MANYFURRY NAMES ALSJSHAHAHHAAHH WHAT-

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What are the characteristics of the Global Address List? Check all that apply.
nignag [31]

Answer:

It is the very last statement (bottom). Also copied to the the client

Explanation:

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Antivirus software products require that you update _____ on a regular basis
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Operating System, as far as I know @[email protected]
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This is for C++: Using a nested for loop output the following pattern to the screen:
olga55 [171]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int r=26,x,y;//defining integer variable  

char c;//defining a character variable

for(x= 1; y<= r; x++)//using for loop for count value

{

for(y= 1; y<= x; y++)//using for loop to convert value in triangle  

{

c=(char)(y+64);//convert value into character  

cout << c;//print character value

}

cout << "\n";//use print method for line break

}

return 0;

}

Output:

Please find the attachment file.

Explanation:

In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop,  in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.

3 0
2 years ago
Using Matlab programming I need to rotate the line defined by x,y by 45 degrees around 2,2
belka [17]

Answer:

% here x and y is given which we can take as

x = 2:2:10;

y = 2:2:10;

% creating a matrix of the points

point_matrix = [x;y];

%  center point of rotation  which is 2,2 here

x_center_pt = x(2);

y_center_pt = y(2);

% creating a matrix of the center point

center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));

% rotation matrix with rotation degree which is 45 degree

rot_degree = pi/4;      

Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];

% shifting points  for the center of rotation to be at the origin

new_matrix = point_matrix - center_matrix;  

% appling rotation  

new_matrix1 = Rotate_matrix*new_matrix;          

Explanation:

We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.

4 0
3 years ago
Applying what formatting option to your excel workbook will make it easier to read when printed out?
blagie [28]
Portrait, as well as 100 percent scale.
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3 years ago
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