The shaded region is a triangle. Triangle area can be determined with formula
a = 1/2 × b × h
From the question, we know that the triangle consists of
base = 10 - 6 = 4 m
and the height is the dimension which is perpendicular to the base,
height = 6 m
Find the triangle area
a = 1/2 × b × h
a = 1/2 × 4 × 6
a = 1/2 × 24
a = 12
The area of the shaded region is 12 m²
Y=-2x+4 the first blank will be your slope and the second blank will be where your line crosses the y intercept
Dy/dx = dy/dt * dt/dx
xy = 4
y + x(dy/dx) = 0 by implicit differentiation.
x(dy/dx) = -y
dy/dx = -y/x
<span>dy/dx = dy/dt * dt/dx dy/dt = -2
</span>
<span>-y/x = -2 * dt/dx
</span>
y/(2x) = dt/dx
dt/dx = y/(2x)
dx/dt = 2x/y
When x = -3, xy = 4, y = 4/x = 4/-3 = -4/3
dx/dt = 2*-3/(-4/3) = -6 *-3/4 = 18/4 = 9/2 = 4.5
dx/dt = 4.5
Answer:
Step-by-step explanation:
4x+y=14
x-2y=8
then;
x=8-2y
substitute;
4(8-2y)+8-2y=14
32-8y+8-2y=14
40-10y=14
26=10y
y=2.6 , work out 4x+2.6=14 to get x
If there aren't any specific requirements for the equation, here are a few choices:
2³ = 8
64 / 8 = 8
2x + 4 = y (where x = 2)
x² - 1 = y (where x = 3)
