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Bad White [126]
3 years ago
13

How do u do mental math for 53 x 7

Mathematics
1 answer:
ikadub [295]3 years ago
7 0
Easy!!!! you first multiply 7 x 5 which is equal to 35 and just add another 0 to that because the number is 50 not 5, so we have 350 and then just multiply 7 x 3 which is 21 and add that up to 350, and the final result being 371
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The area of a rectangle is found by multiplying the length by the width: A = lw. A certain rectangle has an area of x2 + 7x + 12
kupik [55]

Answer:

Option C is correct

l = x+4 unit and w = x+3 unit

Step-by-step explanation:

Area of a rectangle is given by:

A =lw           ....[1]

where

A is the area of rectangle

l is the length of a rectangle

w is the width of a rectangle.

As per the statement:

A certain rectangle has an area of x^2 + 7x + 12

⇒A = x^2+7x+12

Now factor this trinomial :

A = x^2+4x+3x+12

⇒A = x(x+4)+3(x+4)

⇒A=(x+4)(x+3) unit square

On comparing with [1] we have;

l = x+4 unit and w = x+3 unit

Therefore,the length and width of the rectangle are:

l = x+4 unit and w = x+3 unit

7 0
4 years ago
Read 2 more answers
1/4+1/2 find the sum using number line
Arte-miy333 [17]
It's 3/4

no number line provided for me, but if you find the common denominator (4), and convert 1/2 into 2/4, then adding 2/4+1/4 is easy, and equals 3/4
3 0
4 years ago
Find the radius of the sphere with a volume of 32/81π cubic yards. Write your answer as a fraction in simplest form.
alexdok [17]

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=\frac{32\pi }{81} \end{cases}\implies \cfrac{32\pi }{81}=\cfrac{4\pi r^3}{3}\implies \cfrac{96\pi }{81}=4\pi r^3 \\\\\\ \cfrac{96\pi }{324\pi }=r^3\implies \cfrac{8}{27}=r^3\implies \sqrt[3]{\cfrac{8}{27}}=r\implies \cfrac{\sqrt[3]{8}}{\sqrt[3]{27}}=r\implies \cfrac{2}{3}=r

5 0
4 years ago
What's the answer of.. <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4a%20%7B%7D%5E%7B2%7D%20%7D%7B16a%20%7B%7D%5E%7B5%7D%2
KatRina [158]

Answer:

\large\boxed{\dfrac{1}{4}a^{-3}b^3=\dfrac{b^3}{4a^3}}

Step-by-step explanation:

\dfrac{4a^2b^5}{16a^5b^2}\qquad\text{use}\ \dfrac{x^n}{x^m}=x^{n-m}\\\\=\dfrac{4}{16}a^{2-5}b^{5-2}=\dfrac{1}{4}a^{-3}b^3\qquad\text{use}\ x^{-n}=\dfrac{1}{x^n}\\\\=\dfrac{b^3}{4a^3}

3 0
3 years ago
Given right triangle ABCABC with altitude \overline{BD}
mina [271]

Answer:

The correct answer is 4√3

Step-by-step explanation:

Consider the triangle ABC.

BC = 12 units. ∠ B = 90°. Let ∠ C = α°.

Now let us consider the triangle BDC.

DC = 4 units. ∠ D = 90°. Let ∠ C = α°.

We find here the angle C is common between both the triangles.

∴ For ΔABC, cos α° = \frac{BC}{AC} = \frac{BC}{12}

and for Δ BDC, cos α° = \frac{DC}{BC} = \frac{4}{BC}

Now equating both the equations we get,

BC^{2} = 48

⇒ BC = 4√3

The length of BC is 4√3 units.

5 0
3 years ago
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