Answer:
<u> BC = 10 and AD = 30</u>
Step-by-step explanation:
In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.
Since, line AD is sum of AK and KD, then
AD = AK + KD
AD = 10 + 20
AD = 30
Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD
so, BC = KL and AK = LD
KL = AD - LD
KL = 20 - 10
KL = 10
Since, BC = KL then BC = 10
Hence, <u> BC = 10 and AD = 30</u>
Answer:
y = 116°
Step-by-step explanation:
Given that <em>L₁ </em>|| <em>L</em>₂:
The <u>exterior angle theorem</u> states that the measure of an exterior angle of a triangle is equal to the sum of the two opposite and non-adjacent remote interior angles.
Also, ∠y° and ∠2x° are <u>same-side interior angles</u> formed by the intersection of the <em>hypotenuse</em> of the triangle that acts as a transversal to the parallel lines, <em>L₁ </em>and <em>L</em>₂. Given that ∠y° and ∠2x° are <u>same-side interior angles</u>, then it means that they are the supplements of each other, such that the sum of their measures is 180°.
Now that we have established these definitions, we can proceed with the solution.
<u>Equation 1</u>: ∠y° + ∠2x° = 180° ⇒ Same-side interior angles
<u>Equation 2</u>: ∠y° = ∠x° + ∠84° ⇒ exterior angle theorem
Substitute the value of m∠y° from Equation 2 into Equation 1 to solve for the value of x:
∠y° + ∠2x° = 180°
∠x° + ∠84° + 2x° = 180°
Combine like terms:
∠3x° + ∠84° = 180°
Subtract ∠84° from both sides:
∠3x° + ∠84° - ∠84° = 180° -∠84°
∠3x° = 180° - ∠84°
∠3x° = 96°
Divide both sides by 3 to solve for x:
∠x° = 32°
Substitute the value of x into Equation 2 to solve for y:
∠y° = ∠x° + ∠84°
∠y° = ∠32° + ∠84°
∠y° = 116°
Verify whether the values for x and y are correct by substituting their values into Equation 1 and 2:
<h3>Equation 1:</h3>∠y° + ∠2x° = 180°
116° + 2(32)° = 180°
116° + 64° = 180°
180° = 180° (True statement).
<h3>Equation 2:</h3>∠y° = ∠x° + ∠84°
116° = 32° + 84°
116° = 116° (True statement)
Therefore, the correct answer is: y = 116°.