Question

Which value are in the solution set of the compound inequality?

Answer 1

Answer:

Option A and B

Step-by-step explanation:

We have 4(x+3) ≤ 0

        x+3 ≤ 0

        x ≤ -3

We also have $\frac{1}{4x+1}>3$

         $4x+1$

We have x ≤ -3 and $x$

Only A and B satisfies both this conditions.

             

Answer 2

$4(x+3)\leq0\ \ \ \ |:4\\x+3\leq0\ \ \ |-3\\x\leq-3\\\\\dfrac{1}{4}x+1 \ \textgreater \ 3\ \ \ |-1\\\dfrac{1}{4}x \ \textgreater \ 2\ \ \ \ |\cdot4\\x \ \textgreater \ 8\\\\x\leq-3\ or\ x \ \textgreater \ 8\\\\Answer:\\A.\ -6\\B.\ -3\\F.\ 10$