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Musya8 [376]
3 years ago
11

3n + 7 in word form please help me

Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

The product of 3 and a variable n plus 7

Step-by-step explanation:

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Ann studied the effects of watching television on time spent exercising
34kurt

The response variable in the study that Ann has done here can be said to be Time spent exercising.

<h3>What is a response variable?</h3>

This is the name that is used to refer to the dependent variable. This is the variable that is of interest in the study. The goal is to see the changes that occurs in the particular variable based on the actions that another variable would have such as the independent variable.

From this we can see that The response variable in the study that Ann has done here can be said to be Time spent exercising.

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1 year ago
Using the given zero, find one other zero of f(x). i is a zero of f(x).= x4 - 2x3 + 38x2 - 2x + 37.
statuscvo [17]
If i is a zero, -i is also a zero.
The way you get a complex zero is by taking the square root of a negative number. Taking the sqrt (-1) = + and - i
4 0
3 years ago
8
diamong [38]

Answer:

b i think

Step-by-step explanation:

6 0
3 years ago
Which of the following indicates the division property of equality when solving –12x = 48?
vampirchik [111]
A is the answer because I did befor
6 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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