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3 years ago

3n + 7 in word form please help me

Mathematics

1 answer:

scoundrel [369]3 years ago

8 0

Answer:

The product of 3 and a variable n plus 7

Step-by-step explanation:

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Can someone pls help me

Ivan

Answer:

arc EFC = 237°

Step-by-step explanation:

arc DEF = 140°

arc EF = 140° - 83° = 57°

arc DC = arc FG

arc DC = (360° - 140° - 140°)/2 = 40°

arc EFC = arc CG + arc FG = arc EF = 140° + 40° + 57° = 237°

8 0

2 years ago

Help please don’t get it help!!!!!!!

Scorpion4ik [409]

Answer:

10,542,719

Step-by-step explanation:

The circle chart shows you that an estimated 49% of Australia's population has type O blood. Then the number expected to have type O blood is ...

0.49 × 21,515,754 ≈ 10,542,719

_____

You can choose the correct answer by recognizing that 49% is very slightly less than 1/2, so the number with type O blood will be very slightly less than half of 21 million -- about 10.5 million.

8 0

3 years ago

Quadrilateral HGEF is a scaled copy of quadrilateral DCAB. What is themeasurement of lin EG?

lozanna [386]

Answer:

14 units

Explanation:

If quadrilaterals HGEF and DCAB are similar, then the ratio of some corresponding sides is:

$\frac{FH}{BD}=\frac{EG}{AC}$

Substitute the given side lengths:

$\begin{gathered} \frac{6}{3}=\frac{EG}{7} \\ 2=\frac{EG}{7} \\ \implies EG=2\times7 \\ EG=14 \end{gathered}$

The measurement of line EG is 14 units.

3 0

1 year ago

Choose the solutions to the two equation system.<br>6.0 + 3y = 30<br>15+ y = 7

zloy xaker [14]

Answer:

y= -8 or 8

Step-by-step explanation

30-6= 24

24/3=8

y=8

15+y=7

y=-8

3 0

3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.06. How much of each coin can be present wit

SpyIntel [72]

Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:

2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)

106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0

5 0

2 years ago