How should i solve this using an algebraic equation
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Start with why C isn't the answer.
y = 1.8^0 . The power is zero. Anything to the zero power (anything except 0 to the 0 power) is 1. So 1.8^0 is 1 not something else. C assumes that somehow 0,1.8 turns into 1.8. It does not. The second part is also wrong but you don't need it. However here it is.
x = 0 y = 3
x = 1 y = 3 * 1.8 = 5.4
x = 2 y = 3 * 1.8^2 = 3*3.24 = 9.72
You should be able to see that if you multiply 5.4 by 3, you don't get 9.72
C just does not work.
=======
The actual answer is A. That's exactly what the graph does. If you multiply 5.4 * 1.8 you should get 9.72. Just for completeness, I've included the graph.
Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector = square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
The area of the sector = square units
Work backwards.
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root:
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root: