Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k
we have some points
(3,-2) and (6,-26)
input and solve for a and k
(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k
(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k
we have
-2=a+k
-26=4a+k
multiply first equation by -1 and add to second
2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k
-24=3a
divide both sides by 3
-8=a
-2=a+k
-2=-8+k
add 8 to both sides
6=k
the equation is
Answer:
omg i'm so sorry thats the wronge answer i ment this to go to a diffrent question
Step-by-step explanation:
That would be a:-
13x + 32
-----------
13x
Answer:
4
Step-by-step explanation:
You have to find the volume by dividing the diameter in half, which is 1, and then the volume is 4.19, and that rounds to 4.
B
W
The whole circle is pi r^2= 18 times 18 is 324 pi minus the white part