Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
If the parent graph f(x) = x² is changed to f(x) = 2x², the vertex of the parabola will still remain (0, 0) because whenever the equation of a parabola is in the form y = ax², the vertex will always be (0, 0).
Now if <em>a</em> is a big number, the parabola will become narrower.
So it will stretch vertically and become narrower.
Answer:
vertical
Step-by-step explanation:
Answer:
Part 1)
Part 2)
Part 3)
Step-by-step explanation:
step 1
Find the measure of length side FG
In the right triangle EFG
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
step 2
Find the measure of length side EF
In the right triangle EFG
we know that
----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
step 3
Find the measure of angle G
we know that
---> by complementary angles in a right triangle
Answer:
3 dimes and 10 quarters
Step-by-step explanation:
If you add 7 dimes, then the number of dimes and quarters is the same, and the total increases to $3.50. A dime and a quarter have a value together of $0.35. Since there are equal numbers, the value $3.50 must be made up of some quantity of groups with a value of $0.35. That number of groups must be ...
... $3.50/$0.35 = 10
Thus, there are 10 quarters and 10-7 = 3 dimes.
_____
<em>Using an equation</em>
Let q represent the number of quarters. Then the amount Bess has is ...
... 0.10(q -7) +0.25q = 2.80
... 0.35q - 0.70 = 2.80
... 0.35q = 3.50 . . . . . add 0.70 . . . . . . . this should look familiar
... q = 3.50/0.35 = 10