All categories

3 years ago

-2x+19+12x=49 solve for x

Mathematics

2 answers:

MaRussiya [10]3 years ago

5 0

Answer:

X=3

Step-by-step explanation:

Combined liked term

Move constant to the right

Subtract the number

Divide both side by 10

sdas [7]3 years ago

4 0

Answer:

x = 3

Step-by-step explanation:

49 - 19 = 30

-2x - 12x = 10x

30 / 10 = 3

You might be interested in

I’d appreciate itttttttt soooo muchhh if you even do only one, it’s easy but I’m tiredddddd

zubka84 [21]

Answer:

1. x= -1/3

2. y= -4, x= 2

3. y=-2, x=1

Step-by-step explanation:

7 0

2 years ago

Please help me with this

Citrus2011 [14]

I don't know the answer because of how zoomed in it is. But, you could make a cordinate grid and plot all of the numbers. Then, you would connect all of the lines and you will see that one line is missing in the parallelogram. You finish off that line yourself and write down the cordanite that you needed to complete the parallelogram. You will lastly put U=answer (the cordanite you got from finishing off the parallelogram).

5 0

2 years ago

X^2-21.75x=-15.75 what is one solution

Jlenok [28]

Well, there are two solutions.

Add both sides by 15.75 then from here, you can use quadratic formula.

So your answer should be x = -2.44949 or 2.44949.

5 0

3 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$