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ankoles [38]
3 years ago
12

Which transformations will produce similar, but not congruent, figures?

Mathematics
1 answer:
grin007 [14]3 years ago
8 0
<span>Which transformations will produce similar, but not congruent, figures?
</span><span>Square ABCD is rotated 270° clockwise and then dilated by a scale factor of 1/3 to form square AꞌꞌBꞌꞌCꞌꞌDꞌꞌ.
</span><span>Square ABCD is dilated by a scale factor of 4/5 and then translated 1 unit right to form square AꞌꞌBꞌꞌCꞌꞌDꞌꞌ.
</span><span>Square ABCD is translated 8 units right and 8 units up and then reflected across the y-axis to form square AꞌꞌBꞌꞌCꞌꞌDꞌꞌ.
</span>The answers are letters A, C and D
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What are the values of k that make 2x^2 + kx + 11 factorable?
harina [27]
Well K is the sum of two integers so the product equals 2*11, as a Hero pointed out:
ac=2*11=22 k=sum of two integers so now it = to 22

I hope this helps :D
8 0
4 years ago
Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
3 years ago
When the absolute value of the slope gets bigger, the graph of a line gets _____.
Kruka [31]
Longer B is the right answer
4 0
3 years ago
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Fencing cost $10 per foot. Frances had a rectangular garden that is 4 feet wide and 5 feet long . How much money will frances ne
Marizza181 [45]
Answer: $180

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6 0
3 years ago
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Help plz ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!
Yakvenalex [24]

Answer:

-2

Step-by-step explanation:

Let's solve your equation step-by-step.

−(3v+1)+7(6v+6)=−37

Step 1: Simplify both sides of the equation.

−(3v+1)+7(6v+6)=−37

−3v+−1+(7)(6v)+(7)(6)=−37(Distribute)

−3v+−1+42v+42=−37

(−3v+42v)+(−1+42)=−37(Combine Like Terms)

39v+41=−37

39v+41=−37

Step 2: Subtract 41 from both sides.

39v+41−41=−37−41

39v=−78

Step 3: Divide both sides by 39.

39v

39

=

−78

39

v=−2

Answer:

v=−2

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