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Alika [10]
3 years ago
9

Which expression is equivalent to

Mathematics
2 answers:
sergejj [24]3 years ago
7 0

Answer:

x^{\frac{1}{8} } y^{8}

Step-by-step explanation:

x^{1/4 \times 1/2} y^{16 \times 1/2}

x^{1/8} y^{8}

aleksley [76]3 years ago
7 0

Answer:

x^1/8 y^8

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

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Helpppp :,[ also stay safe and have a great day!!!!!!!!!!!!!!!!!!!!!!1111
serious [3.7K]

Answer:

35÷7=5

Step-by-step explanation:

we have 7 small boxes in an oval and there are 5 ovals

All the boxes add up to 35

4 0
3 years ago
Read 2 more answers
Three roots of a polynomial equation with real coefficients are 3, 5 – 3i, and −3i. Which of the following numbers must also be
Leviafan [203]

Answer is D (−3, 5 + 3i, and 3i)

4 0
3 years ago
1. The Senior Class of Great Ridge High School and Ann Arbor High School are planning a trip to Six Flags Theme Park. Great Ridg
Zanzabum

Answer:

A)14v + 16b = 1152

10v + 13b = 925

B)Number of students in a van = 8

Number of students in each bus = 65

C) Elimination method was easier.

Step-by-step explanation:

Let v be the number of students in a van

Let b be number of students in a bus

A) We are told the first school can fill 14 vans and 16 buses with 1152 students

Thus;

14v + 16b = 1152 - - - - - (eq 1)

Also,we are told that the second school can fill 10 vans and 13 buses with 925 students.

Thus;

10v + 13b = 925 - - - - (eq 2)

B) To solve this we will use elimination method.

Multiply eq (1) by 5 and multiply eq (2) by 7 to give;

70v + 80b = 5760 - - - - eq(3)

70v + 91b = 6475 - - - - - eq(4)

Subtract eq(3) from eq(4) to give;

91b - 80b = 6475 - 5760

11b = 715

b = 715/11

b = 65

Put 65 for b in eq(3) to give;

70v + 80(65) = 5760

70v = 5760 - 80(65)

70v = 560

v = 560/70

v = 8

Number of students in a van = 8

Number of students in each bus = 65

C) Elimination method was used because in both equations, we had different digits attached and so it would have been more tedious to use substitution method or graphical method. Thus, elimination method was more easier.

7 0
3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
The weight of a full steel bead tire is approximately 800 grams, while a lighter wheel weighs only 700 grams. What is the weight
SIZIF [17.4K]

800= about 1.76 lbs

700= about 1.54 lbs


(there are about 453.5 grams in a pound

4 0
3 years ago
Read 2 more answers
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