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Alika [10]
3 years ago
9

Which expression is equivalent to

Mathematics
2 answers:
sergejj [24]3 years ago
7 0

Answer:

x^{\frac{1}{8} } y^{8}

Step-by-step explanation:

x^{1/4 \times 1/2} y^{16 \times 1/2}

x^{1/8} y^{8}

aleksley [76]3 years ago
7 0

Answer:

x^1/8 y^8

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

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Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.
Sladkaya [172]

Answer:

The solution is  \frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

Step-by-step explanation:

From the question

    The function given is  f(x) =  \frac{e^{2x}}{ 25 + e^{4x}} dx

The  indefinite integral is  mathematically represented as

          \int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx

Now  let  e^{2x} =  u

=>   \frac{du}{dx} 2e^{2x}

=>   2 e^{2x}dx =  du

So

\int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx =  \int\limits  {\frac{1}{ 2(25 + u^2)} } \, du

= \frac{1}{2} \int\limits  {\frac{1}{ 25 + u^2)} } \, du

=  \frac{1}{2} \int\limits  {\frac{1}{ 5^2 + u^2)} } \, du

= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5}  +  C

Now substituting for  u

\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

3 0
3 years ago
Find the midpoint from (-2,-2) to (6,6)
timama [110]
(2,2)


(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
4 0
2 years ago
Read 2 more answers
which statement is true about the equations –3x 4y = 12 and x1/4 – 1/3y = 1? the system of the equations has exactly one solutio
finlep [7]
If you would like to solve the system of equations, you can do this using the following steps:

-3x + 4y = 12
x * 1/4 - 1/3 * y = 1 ... x * 1/4 = 1 + 1/3 * y ... x = 4 + 4/3 * y
_____________
<span>-3x + 4y = 12
</span>-3 * (4 + 4/3 * y) + 4y = 12
-12 - 4y + 4y = 12
-12 = 12
-12 - 12 = 0
-24 = 0

The correct result would be: <span>the system of the equations has no solution; the two lines are parallel.</span>
4 0
3 years ago
What is a solutions of x^2-2x+10=0?​
Debora [2.8K]

Answer:

x = 1± 3i

Step-by-step explanation:

x^2-2x+10=0

We can complete the square to solve by subtracting 10 from each side

x^2-2x+10-10=-10

x^2 -2x = -10

We need to add (2/2) ^2  to each side or 1

x^2 -2x+1 = -10 +1

x^2 -2x+1 = -9

The left side factors into (x- (2/2) ) ^2

(x-1) ^2 = -9

Take the square root of each side

sqrt((x-1) ^2 =± sqrt(-9)

x-1 = ±sqrt(-1) sqrt(3)

Remember the sqrt(-1) = i

x-1 = ± 3i

Add 1 to each side

x-1+1 = 1± 3i

x = 1± 3i

8 0
2 years ago
I need help on number 8​
Marta_Voda [28]

Answer:

kojnlvhjh

Step-by-step explanation:

3 0
2 years ago
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