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3 years ago

I NEED HELP PLEASE FAST ILL PICK BRAINLIEST AND A LOT OF POINTS PLZ

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

Answer:

a=38, b=54 ,c=54

WINSTONCH [101]3 years ago

5 0

Answer:

a=38 b=54 c=46

Step-by-step explanation:

c= (180-88)/2 b= 180-(a+88) a=180-142

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What will the sale price be of a t-shirt that has an original price of $24.99 and is on sale for 30% off

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Original price $24.99

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Or we can say that it will be 70% of the initial price

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24,99 . 70% = 24,99 . 70/100 = 17,493

The price will be $17,493

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2 years ago

A zip line starts on a platform that is 404040 meters above the ground. The anchor for the zip line is 198198198 horizontal mete

lubasha [3.4K]

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3 years ago

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The mean age of 11 women in an office is 31 years old.

BlackZzzverrR [31]

Answer: 30.2

Explanation:

The mean is calculated by taking the sum of the values and dividing by the count.

For instance, for the 6 women, with the mean being 31, we can see that the ages summed to 186:

186

And we can do the same for the men:

116

And now we can combine the sum and count of the men and women to find the mean for the office:

186

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302

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Step-by-step explanation:

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2 years ago

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Solve 4√2 + 5√4 and explain if the answer is rational or irrational

USPshnik [31]

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5 0

2 years ago

An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.

MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years, there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is $\frac{21}{3000000}==0.000007$ .

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by $q$ .

$q=7\times 10^{-6}=0.000007$ .

So, the probability of survive, $p=1-q$

$\Rightarrow p=1-7\times 10^{-6}=0.999993.$

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

$=\binom(n,r)p^rq^{n-r}$

$=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}$

$=(0.999993)^{48}=0.999664$ (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total $n$ skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

$0.9=\binom {n }{r} p^rq^{n-r}$

Here, r=n.

$\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}$

$\Rightarrow 0.9=p^n$

$\Rightarrow 0.9=(0.999993)^n$

$\Rightarrow \ln(0.9)=n\ln(0.999993)$ [ taking $\log_e$ both sides]

$\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}$

$\Rightarrow n=15051.45$

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0

3 years ago