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Fofino [41]
3 years ago
10

Which expression is equivalent to Cube root of 343 x Superscript 9 Baseline y Superscript 12 Baseline z Superscript 6?

Mathematics
2 answers:
Leokris [45]3 years ago
8 0

9514 1404 393

Answer:

  7x^3y^4z^2

Step-by-step explanation:

  \displaystyle\sqrt[3]{343x^9y^12z^6}=\sqrt[3]{(7x^3y^4z^2)^3}=\boxed{7x^3y^4z^2}

baherus [9]3 years ago
5 0

Answer:

\small \sf \leadsto \:  7x {}^{3}y {}^{6}z {}^{2}

Step-by-step explanation:

\small \sf \leadsto \:  \sqrt[3]{343 \: x {}^{9} \: y{}^{12}  \: z {}^{6} }

\small \sf \leadsto \:  \sqrt[3]{7x {}^{3}y {}^{6}z {}^{2}   }

\small \sf \leadsto \:  7x {}^{3}y {}^{6}z {}^{2}

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253 km per hour

Step-by-step explanation:

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If u = 3 inches, v = 4 inches, w = 7 inches, x = 7 inches, y = 8 inches, and z = 4 inches, what is the area of the object?
kvasek [131]

Answer:270

Step-by-step explanation:

Length:

U = 3 inches

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Width:

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2 years ago
100 POINTS <br> Evaluate the derivative of the function number 38
patriot [66]

Answer:

 1/ sqrt(1+ln^2(x))    * 1/(ln^2x +1) * 1/x

Step-by-step explanation:

f(x) = sin (tan^-1 (ln(x)))  

u substitution

       d/du (sin u)  * du /dx

            cos (u) * du/dx

Let u =(tan^-1 (ln(x)))     du/dx =d/dx  (tan^-1 (ln(x)))

v substitution

                                             Let v = ln x                dv/dx = 1/x

                                              d/dv  (tan ^-1 v)  dv/dx

                                                          1/( v^2+1) * dv/dx

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Substituting this back in for  du/dx

cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)

cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

 1/ sqrt(1+ln^2(x))     * 1/(ln^2x +1) * 1/x

                                           

8 0
3 years ago
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A warehouse contains 55 boxes. Then a truck delivers a number of boxes at 12:00 p.m. and the team begins to unload them immediat
vredina [299]

Answer:

25

Step-by-step explanation:

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2 years ago
A customer from Cavallaro's Fruit Stand picks a sample of 5 oranges at random from a crate containing 75 oranges, of which 6 are
boyakko [2]

Answer:

0.341 is the probability that the sample contains 1 or more rotten oranges.

Step-by-step explanation:

We are given the following information:

We treat rotten as a success.

Number of oranges = 75

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P(Rotten orange) =

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Then the number of rotten oranges follows a binomial distribution, where

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Now, we are given n = 5

We have to evaluate:

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0.341 is the probability that the sample contains 1 or more rotten oranges.

7 0
4 years ago
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