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Fofino [41]
3 years ago
10

Which expression is equivalent to Cube root of 343 x Superscript 9 Baseline y Superscript 12 Baseline z Superscript 6?

Mathematics
2 answers:
Leokris [45]3 years ago
8 0

9514 1404 393

Answer:

  7x^3y^4z^2

Step-by-step explanation:

  \displaystyle\sqrt[3]{343x^9y^12z^6}=\sqrt[3]{(7x^3y^4z^2)^3}=\boxed{7x^3y^4z^2}

baherus [9]3 years ago
5 0

Answer:

\small \sf \leadsto \:  7x {}^{3}y {}^{6}z {}^{2}

Step-by-step explanation:

\small \sf \leadsto \:  \sqrt[3]{343 \: x {}^{9} \: y{}^{12}  \: z {}^{6} }

\small \sf \leadsto \:  \sqrt[3]{7x {}^{3}y {}^{6}z {}^{2}   }

\small \sf \leadsto \:  7x {}^{3}y {}^{6}z {}^{2}

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Answer:

The answer is

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Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

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Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

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3 years ago
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Step-by-step explanation:

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