Question

The area of a rectangle is (27x5 + 9x4 - 18x3) square feet. The width of the rectangle is 9x2 feet. What is the length of the rectangle?
DO NOT INCLUDE PARENTHESIS IN YOUR ANSWER

Answer 1

If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺

Answer 2

Answer:

The length of the rectangle is given by 3x^3+x^2-2x

Step-by-step explanation:

We have been given that

area of rectangle is $A=27x^5 + 9x^4 - 18x^3$

The width of the rectangle is $w=9x^2$

We know the area of rectangle is given by

$A=lw\\\\l=\frac{A}{w}$

On substituting the known values, we get

$l=\frac{27x^5 + 9x^4 - 18x^3}{9x^2}$

On simplifying this, we get

$l=\frac{27x^5}{9x^2} +\frac{9x^4}{9x^2} -\frac{18x^3}{9x^2} \\\\l=3x^3+x^2-2x$

Therefore, the length of the rectangle is given by 3x^3+x^2-2x