Answer:
Step-by-step explanation:
Let the ends of the given segment are A and B.
Coordinates of A → (8, 6)
Coordinates of B → (12, 12)
If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,
(x, y) → (kx, ky)
If k = 
(x, y) → 
By this rule coordinates of the image points of A and B will be,
A(8, 6) → 
→ A'(5.3, 4)
B(12, 12) → 
→ B'(8, 8)
Now we can get the image of segment AB after dilation by a scale factor of .
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
