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netineya [11]
3 years ago
15

What is the slope of the line?

Mathematics
1 answer:
liberstina [14]3 years ago
3 0

Answer:

y= -x-2

Step-by-step explanation:

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HELP I NEED HELP ASAP
Phantasy [73]
I think the answer is 2.5
8 0
2 years ago
Pedro has a student loan of $62,845. This loan has a simple interest rate of 7% per year. What is the amount of interest that Pe
Nat2105 [25]
I believe it would be $4,399.15 because if you use the formula I=P*R*T
P=62,845
R=0.07 or 7%
T=1 year period
So overall your equation is 62845*0.07*1=$4,399.15
Now at this point the interest is added onto the principal amount to figure out some new amount after one year so:
62845.00+4399.15=$67,244.15
6 0
3 years ago
say you want to find the rate of simple annual interest for 2 year loan the bank charges $560 interest for the $2,000 loan what
romanna [79]
28% interest would be your answer, you just divide 560/2000=.28
5 0
3 years ago
Liam, Sarah and Emily shares some money in the ratio 2:3:7.
nignag [31]

Answer:

Emily got 7x

Liam got 2x

7x = 2x + 80

5x = 80

x = 16

Liam got 32, <u>Sarah got 48</u>, and Emily got 112

Step-by-step explanation:

3 0
3 years ago
What is the perimeter of angle DEF to the nearest tenth of a unit?<br> helppppp<br> tysm
hammer [34]
<h3>Answer:  36.4 units  (choice A)</h3>

===========================================================

Explanation:

Let's use the distance formula to find the distance from D to E

D = (x_1,y_1) = (-7,2) \text{ and } E = (x_2, y_2) = (3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-7-3)^2 + (2-4)^2}\\\\d = \sqrt{(-10)^2 + (-2)^2}\\\\d = \sqrt{100 + 4}\\\\d = \sqrt{104}\\\\d = \sqrt{4*26}\\\\d = \sqrt{4}*\sqrt{26}\\\\d = 2\sqrt{26}\\\\d \approx 10.198\\\\

Note: uppercase D refers to the point, while lowercase d is the distance from D to E.

The length of segment DE is roughly 10.198 units long.

----------------

Repeat for the distance from E to F.

E = (x_1,y_1) = (3,4) \text{ and } F = (x_2, y_2) = (5,-7)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (4-(-7))^2}\\\\d = \sqrt{(3-5)^2 + (4+7)^2}\\\\d = \sqrt{(-2)^2 + (11)^2}\\\\d = \sqrt{4 + 121}\\\\d = \sqrt{125}\\\\d = \sqrt{25*5}\\\\d = \sqrt{25}*\sqrt{5}\\\\d = 5\sqrt{5}\\\\d \approx 11.1803\\\\

Segment EF is roughly 11.1803 units long.

----------------

Repeat for the distance from F to D.

F = (x_1,y_1) = (5,-7) \text{ and } D = (x_2, y_2) = (-7,2)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(5-(-7))^2 + (-7-2)^2}\\\\d = \sqrt{(5+7)^2 + (-7-2)^2}\\\\d = \sqrt{(12)^2 + (-9)^2}\\\\d = \sqrt{144 + 81}\\\\d = \sqrt{225}\\\\d = 15\\\\

Unlike the others, this result is exact.

----------------

Add up the three segment lengths to get the perimeter

DE + EF + FD

10.198 +  11.1803 + 15

36.3783

The perimeter is approximately 36.3783 units which rounds to <u>36.4</u>

The answer has been confirmed with GeoGebra.

4 0
2 years ago
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