Step-by-step explanation: The first thing you should do is combine any like terms. For you this means combining 4p and -7p. This gives you -3p+5=-1. Then, subtract 5 on each side to eliminate the 5. This gives you -3p=-6. Divide by -3 on each side to allow the p to stand alone. This makes p=2.

8 0

2 years ago

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4. See if you can find "like-terms" in the expression and

WITCHER [35]

Answer:

After finding like terms and solving, we get $\mathbf{3x^2+3x+16}$

Step-by-step explanation:

We need to find like terms and simplify the expression $4- 2x + x^2 + 5x + 12 + 2x^2$

Like terms: The terms who have same variable and exponent are called like terms.

So, Combining like terms and solving:

$4- 2x + x^2 + 5x + 12 + 2x^2\\=4+12-2x+5x+x^2+2x^2\\Now \ solving:\\=16+3x+3x^2\\Rearranging \ the \ terms:\\=3x^2+3x+16$

So, after finding like terms and solving, we get $\mathbf{3x^2+3x+16}$

<u><em>Note: In the question given we have - and + sign with the term 5x</em></u> i.e 4- 2x + x^2 -+ 5x + 12 + 2x^2

I have solved using +5x, but if the term is -5x then the solution will be:

$4- 2x + x^2 - 5x + 12 + 2x^2\\=4+12-2x-5x+x^2+2x^2\\Now \ solving:\\=16-7x+3x^2\\Rearranging \ the \ terms:\\=3x^2-7x+16$

So, the answer will be: $\mathbf{3x^2-7x+16}$

7 0

2 years ago

Which pair of numbers is relatively prime?

AnnZ [28]

The answer is C, as both numbers are only both divisible by 1.

6 0

2 years ago

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Factorise <img src="https://tex.z-dn.net/?f=2t%5E2%2B5t%2B2" id="TexFormula1" title="2t^2+5t+2" alt="2t^2+5t+2" align="absmiddle

blondinia [14]

Answer: $\displaystyle\ \large \boldsymbol{ 2t^2+5t+2= {(2t+1) (t+2)}}$

Step-by-step explanation:

$\displaystyle\ \large \boldsymbol{} 2t^2+5t+2=0 \\\\2t^2+\underbrace{4t+t}_{5t}+2=0 \\\\ (2t^2+4t)+(t+2)=0 \\\\ 2t(\underline{t+2})+(\underline{t+2})=0 \\\\ \boxed{(2t+1) (t+2)=0 }$

3 0

2 years ago