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aliina [53]
3 years ago
10

1 5/2 as a whole number

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

3 1/2

Step-by-step explanation:

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Please help me
Kruka [31]

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

y = 4^2 - 4×4 = 16 - 16 = 0

now 2nd equation

y = 2x^2 + x

x = -2

y = 2 (-2)^2 + (-2)= 8-2 = 6

x = -1

y = 2 (-1)^2+(-1)= 2-1 = 1

x = 0

y = 2(0)^2 +0 = 0

x = 1

y = 2 (1)^2 + 1 = 3

x = 2

y = 2(2)^2+2= 8 + 2 = 10

6 0
3 years ago
On the first circle, what segment is a diameter? How long is it?
stiv31 [10]

Answer:

The segment that is the diameter is EB

It is 8 cm long

Step-by-step explanation:

6 0
3 years ago
What is the square root of 683
Mashutka [201]

Answer:

The square root of six hundred and eighty-three √683 = 26.13426869074



4 0
3 years ago
Read 2 more answers
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
What is sinB?<br>15/17 <br>8/17<br>8/15<br>15/8<br>​
dusya [7]

Answer:

817

Step-by-step explanation:

7 0
3 years ago
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