By SAS property, ABC ≅ DCB.
<h3>How to prove the deductions</h3>
In this question we have to proof ABCD has congruent diagonal. By SAS property and reflexive property it can be proved as follows:
Given:
ABCD is a rectangle.
Prove:
Diagonal AC ≅ Diagonal BD
From the question,
As we can see that, ABCD is a rectangle, it is also a parallelogram.
Thus, ABCD is a parallelogram, opposite sides of a parallelogram are congruent.
⇒ AB ≅ DC
⇒ BC ≅ BC (Reflexive Property of Congruence)
Hence, ∠ABC and ∠DCB are right angles by the definition of rectangle.
∠ABC ≅ ∠DCB (all right angles are congruent)
Therefore, by SAS property, ABC ≅ DCB.
⇒ segment AC ≅ segment BD
Learn more about rectangular congruency here:
brainly.com/question/7162498
#SPJ1
Answer:
Good luck
Step-by-step explanation:
<u>(50)</u> half it
(<u>25</u>) (<u>25</u>)
(12) (12)
(12.5) (12.5) (12.5) (12.5)
(12) (12) (12) (12)
0.5 + 0.5 + 0.5 + 0.5 = 2 (0.5= 1/2 or 0.5 or 0.50)
more examples: (2/4) (3/6) (4/8) (5/10)
So you are gonna have four holes and two twelves
(12/12) (12/12) (12/12) (12/12) (2/12)
Answer:
3x³ + x² + x + 1
= 3x³ - 3x² + 4x² - 4x + 5x - 5 + 6
= 3x²(x - 1) + 4x(x - 1) + 5(x - 1) + 6
= (x - 1)(3x² + 4x + 5) + 6
but 3x³ + x² + x + 1 = (x - 1).Q(x) + R
=> Q(x) = 3x² + 4x + 5
R = 6
Tell him to stop buying shoes, you wouldnt have this questions.
that would be 1/2 :P
