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Tamiku [17]
2 years ago
12

 help please with these 2 !!!! i’ll give brainliest !

Mathematics
2 answers:
Alborosie2 years ago
8 0
1- hypotenuse
2- adjacent
Westkost [7]2 years ago
5 0

Answer:

2 nd question _opposite

1st question_hypotnuse

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Anon25 [30]
The answer to the equation is -580
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Solving Inequalities, 2 parts
Pepsi [2]

Answer:

When solving it the answer is -1/6 is less than or equal to x less than or equal to 3/2

Step-by-step explanation:

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3 years ago
What is the range of the function<br> f(x) = = 3x + 2 in the domain -2
djyliett [7]

Answer:

The range is:

{-4, 1, 2, 5, 8}

Step-by-step explanation:

Given the function

f(x)=3x+2

  • We know that the domain of a function is the set of input or argument values for which the function is real and defined.

As the domain interval -2 ≤ x ≤ 2

i.e. the values in the domain = {-2, -1, 0, 1, 2}

  • We also know that the range of a function is the set of values of the dependent variable for which a function is defined.

As the domain interval -2 ≤ x ≤ 2

Putting all the x-values in the domain interval in the function

so

putting x=-2 in the function

f(x)=3x+2

f(-2)=3(-2)+2=-6+2=-4

putting x=-1 in the function

f(x)=3x+2

f(-1)=3(-1)+2=-3+2=1

putting x=0 in the function

f(x)=3x+2

f(0)=3(0)+2=0+2=2

putting x=1 in the function

f(x)=3x+2

f(1)=3(1)+2=3+2=5

putting x=2 in the function

f(x)=3x+2

f(2)=3(2)+2=6+2=8

Thus, when we put the domain values, the corresponding range values are:

x           y

-2         -4

-1           1

0           2

1             5

2            8

Therefore, the range is:

{-4, 1, 2, 5, 8}

8 0
3 years ago
Find the derivative of <br>y = arcsin(x)​
natta225 [31]

Answer:

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

Step-by-step explanation:

As khown the derivative of arcsin(x) is;

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

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3 years ago
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200 because I’m getting free vids if
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