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Nat2105 [25]
3 years ago
12

Create an expression that is equivalent to x + 2

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Answer:

2 + x

2 + (x)

x + (2)

Step-by-step explanation:

Switch them around.

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If Tom runs 3.5 miles in 29.4 minutes, how many hours would it take him to run 26 miles? Show your work.
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

3.5 miles/(29.4 minutes)

26 miles × (29.4 minutes)/(3.5 miles) = 218.4 minutes

218.4 minutes × (1 hour)/(60 minutes) = 3.64 hours

4 0
3 years ago
Which property would allow you to use mental computation to simplify the problem 27 + 15 + 3 + 5? additive identity additive inv
Fofino [41]

Answer:

Commutative Property

Step-by-step explanation:

Additive Identity: If you add a real number to zero or add zero to a real number, then you get the same real number back.

Additive Inverse: When you add the same number but reversed sign, you get 0.

Commutative Property: a + b = b + a

Addition distributive property: a(b+ c) = ab + ac.

In this case, we use the commutative property:

27 + 15 + 3 + 5 = 27 + 3 + 15 + 5.

We know that 27 + 3 = 30 and 15 + 5 = 20, so we get 50 quickly using mental math.

5 0
3 years ago
Read 2 more answers
If you had to simplify 15/24 what would it be
Effectus [21]

If I had to simplify 15/24 it would be 5/8


8 0
3 years ago
Read 2 more answers
Jillian is making accessories for the soccer team. She uses 667.43 inches of fabric on headbands for 27 players and 4 coaches. S
gulaghasi [49]

Answer:

21.53 in of fabric on headbands

7.67 in of fabric on wristbands.

Step-by-step explanation:

Step one:

given data

the total amount of person players plus coaches= 27+4= 31

for each person, she uses = 667.43/31= 21.53 in of fabric on headbands

She also uses 237.87inches of fabric on wristbands for just the players

For each player, she will use= 237.87/31= 7.67 in of fabric

Hence for each player, she used

21.53 in of fabric on headbands

7.67 in of fabric on wristbands

4 0
3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
3 years ago
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