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2 years ago

Evaluate help please!

Mathematics

1 answer:

UNO [17]2 years ago

3 0

<h2><u>ABSOLUTE VALUE</u></h2>

The absolute value of a number is the distance from 0 to that number. The distance is positive, hence, the absolute value is always a positive number.

<h3>Exercise</h3>

Replace the value of x:

$| x - 8 |$

$| -4 - 8 |$

$| -12 | = \large{\boxed{12}}$

The absolute value of a number is the numerical value of the number, without regard to its sign.

<h3><u>Answer.</u> 12</h3>

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Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

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1 year ago

Someone knows what number multiplied twice by the same can give me results 203!!!!!

sineoko [7]

Answer:

i will help you.......

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2 years ago

Find the measure of angle x

Triss [41]

Answer:

it is heptagon and sum of interior angles of heptagon is 900 °

123°+131°+ 125°+124°+x 129°+132° = 900°

764° +x = 900 °

x = 900°-764°

x = 136°

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2 years ago

Plz help... must show steps....will pick brainiest Solve, finding all solutions in [0,2pi)

Triss [41]

A graphing calculator shows solutions to be
.. x = {π/4, 2.034, 5π/4, 5.176}

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Asked and answered elsewhere.
brainly.com/question/8691400

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3 years ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Two students in t

melomori [17]

Answer:

The system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

In <u>5 minutes</u>, each student will have <u>30</u> flash cards.

Step-by-step explanation:

Given:

Number of flash cards already made by Tristan = 5

Number of flash card Tristan makes in 1 min = 5

Number of flash card Josh makes in 1 min = 6

We need to find the How long will Josh have same number of flashcards.

Also We need to find how many flashcards will each student have at that point.

Solution:

Let the number of minutes be $'x'$ .

Now we can say that;

Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Tristan = $5+5x$

Also We can say that;

Total number of flash cards made by Josh is equal Number of flash card Josh makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Josh = $6x$

Hence the system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

Now to find the number of minutes when both would have same number of flash cards we will make both the equation equal.

so we get;

$5+5x=6x$

On solving we get;

Combining like terms we get;

$6x-5x=5\\\\x=5\ mins$

Hence It would take 5 minutes when both will have same number of flash cards.

To find the number of flash cards each would had at that time we will substitute value of $x=5$ in the system of equations.

so we get;

number of flash cards made by Tristan = $5x+5 = 5\times5+5=25+5=30$

number of flash cards made by Josh = $6x =6\times 5 =30$

Hence In <u>5 minutes</u>, each student will have <u>30</u> flash cards.

6 0

2 years ago