Answer:
![\large\boxed{\sqrt{137}\approx11.7}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Csqrt%7B137%7D%5Capprox11.7%7D)
Step-by-step explanation:
The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have two points (1, -5) and (-3, 6). substitute:
![d=\sqrt{(-3-1)^2+(6-(-5))^2}=\sqrt{(-4)^2+11^2}=\sqrt{16+121}=\sqrt{137}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-3-1%29%5E2%2B%286-%28-5%29%29%5E2%7D%3D%5Csqrt%7B%28-4%29%5E2%2B11%5E2%7D%3D%5Csqrt%7B16%2B121%7D%3D%5Csqrt%7B137%7D)
99 km ... 9 liters
x km ... 12 liters
If the relationship is proportional, we have
![\frac{99}{x} = \frac{9}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B99%7D%7Bx%7D%20%3D%20%5Cfrac%7B9%7D%7B12%7D%20)
from where
The answer is 132 kilometers.
the answer should be C. 5.27
Answer:
23) x= 3, y = 4
24) Any (x,y) values where x = 1.5 - 2y
Step-by-step explanation:
For the first system(23), it goes like this
[1 2 | 7]
[2 1 | 8]
We need to do L2 = L2 - 2L1, so now it is
[1 2 | 7]
[0 -3 |-6]
So, now we have:
-3y = -6 *(-1)
3y = 6
y = 2
x + 2y = 7
x + 4 = 7
x = 3
Now for system 24, we have:
[-1 2 | 1.5]
[2 -4| 3]
We do L2 = L2 + 2L1, so we have:
[-1 2 | 1.5]
[0 0| 0]
So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.