By finding the maximum common factor between the number of spoons, we conclude that he must put 6 teaspoons per bag.
There will be 8 bags in total.
<h3>How many teaspoons of spice should the clerk put in each bag?</h3>
We know that the store clerk has 18 teaspoons of cinnamon and 30 spoons of nutmeg.
Now, we want to put these in bags, such that each bag contains the same number of teaspoons.
Then the number of teaspoons per bag must be a common factor of 30 and 18. (the minimum number of bags is what we get when we select the maximum common factor).
Decomposing these two numbers gives:
30 = 2*3*5
18 = 2*3*3
Then the maximum common factor is 2*3 = 6
This means that we need to put 6 teaspoons per bag.
And the total number of teaspoons is 30 + 18 = 48, dividing that by 6 we get:
48/6 = 8
There will be 8 bags.
If you want to learn more about common factors:
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Do the split method, by splitting it in the middle
Factor 3x^3 + 4x^2 and -15x - 20 seperately
x^2 (3x + 4) - 5(3x + 4)
(x^2 - 5)(3x + 4) is your answer
hope this helps
Answer:
-14
Step-by-step explanation:
The sum (addition) of the three numbers would be -14 because -12+-5 is -17. Then, -17+3 would be -14.
Answer:
The answer is (A) Economies of scale define how cost changes with output, and returns to scale define how output changes with input usage
Step-by-step explanation:
Economies of scale show the effect of an increased output level on unit costs, Economies of Scale refer to the cost advantage experienced by a firm when it increases its level of output. The advantage arises due to the inverse relationship between per-unit fixed cost and the quantity produced. The greater the quantity of output produced, the lower the per-unit fixed cost.
Returns to scale focuses only on the relationship between input and output quantities. Returns to scale is the variation, or change, in productivity that is the outcome from a proportionate increase of all the input.
You use the slope formula to classify a quadrilateral as a parallelogram or rectangle. you use the distance formula to see if it is a trapezoid.