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gregori [183]
3 years ago
15

Camilla has 1\2 pound of raisins that she will divide evenly into 5 bags.Shade the diagram to show the fractional part of a poun

d that will be in each bag.Then write the fraction?
Mathematics
2 answers:
storchak [24]3 years ago
6 0
1/10 hope this helps
Vlad1618 [11]3 years ago
5 0
The answer is 1/10

If you do 1/2 divided by 5 you will get 0.1 or 1/10
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NemiM [27]
First You Need To Convert 3/4 And 1/3 To A LCD Of 12. 4/12 Divided By 9/12. You Can Flip The Second # And Then Multiply Across. 4/12 Times 12/9 OR 1/3 Times 4/3. Four Ninths Is The Final Answer. 4/9.
8 0
3 years ago
Calcium is an essential nutrient for strong bones and for controlling blood pressure and heart beat. Because most of the body’s
irakobra [83]

Answer:

No, because the 95% confidence interval contains the hypothesized value of zero.

Step-by-step explanation:

Hello!

You have the information regarding two calcium supplements.

X₁: Calcium content of supplement 1

n₁= 12

X[bar]₁= 1000mg

S₁= 23 mg

X₂: Calcium content of supplement 2

n₂= 15

X[bar]₂= 1016mg

S₂= 24mg

It is known that X₁~N(μ₁; σ²₁), X₂~N(μ₂;δ²₂) and σ²₁=δ²₂=?

The claim is that both supplements have the same average calcium content:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

The confidence level and significance level are to be complementary, so if 1 - α: 0.95 then α:0.05

since these are two independent samples from normal populations and the population variances are equal, you have to use a pooled variance t-test to construct the interval:

[(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2;1-\alpha /2} * Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-/2}= t_{25;0.975}= 2.060

Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} }= \sqrt{\frac{11*529+14*576}{12+15-2} } = 23.57

[(1000-1016)±2.060*23.57*\sqrt{\frac{1}{12} +\frac{1}{15} }]

[-34.80;2.80] mg

The 95% CI contains the value under the null hypothesis: "zero", so the decision is to not reject the null hypothesis. Then using a 5% significance level you can conclude that there is no difference between the average calcium content of supplements 1 and 2.

I hope it helps!

3 0
2 years ago
Difference quotient
Nina [5.8K]
f(x)=5x^2-5x-6
\\ \quad \\

\begin{cases}
f(\boxed{x+h})=5(\boxed{x+h})^2-5(\boxed{x+h})-6
\end{cases}\qquad thus
\\ \quad \\
\cfrac{f(x+h)-f(x)}{h}\qquad \textit{will be then}
\\ \quad \\
\cfrac{[5({x+h})^2-5({x+h})-6]\quad -\quad [5x^2-5x-6]}{h}
\\ \quad \\
\cfrac{[5(x^2+2xh+h^2)-5(x+h)-6]-[5x^2-5x-6]}{h}


\cfrac{\underline{5x^2}+10xh+5h^2\underline{-5x}-5h\underline{-6}\underline{-5x^2}\underline{+5x}\underline{+6}}{h}\impliedby \textit{canceling those ones}
\\ \quad \\
\cfrac{10xh+5h^2-5h}{h}\impliedby \textit{common factor}
\\ \quad \\
\cfrac{5\underline{h}(2x+h-1)}{\underline{h}}

and surely, you'd know what that is
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HELP! What is the answer? (NO EXPLANATION NEEDED!)
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