Answer:
for this case we have the following functions:
f (x) = x + 8
g (x) = -4x - 3
Subtracting the functions we have:
(f - g) (x) = f (x) - g (x)
(f - g) (x) = (x + 8) - (-4x - 3)
Rewriting:
(f - g) (x) = x + 8 + 4x + 3
(f - g) (x) = 5x + 11
Answer:
D. (f - g) (x) = 5x + 11
Answer:
19
Step-by-step explanation:
BODMAS
Brackets.
Of
Division
Multiplication
Addition and
Subtraction
go according to the BODMAS rule and solve the division first
24-(16÷4)×2+3
Then solve the multiplication part
24-(4×2)+3
Now solve like a regular sum
24-8+3
16+3
19
N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
Answer: What is your question?
