Answer:
2x +3y=1⇒equation 1
3x=2y+8
3x-2y=8⇒equation 2
by elimination method,
2x+3y=1 ×2
3x-2y=8 ×3
4x+6y=2
9x-6y=24
cut 6y and -6y
4x+6y=2
9x-6y=24
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13x+0=26
13x=26
x=26/13
x=2
substitute x=2 in equation 1
2(2)+3y=1
4+3y=1
3y=1-4
3y=-3
y=-3/3
y=-1
therefore, x=2 and y=-1
hope it helps u!
Step-by-step explanation:
The wind has a speed of w and a direction α with the vertical. The x component of that speed is w sin α. The y component is -w cos α.
In order to stay on the north trajectory AB, the plane must have a horizontal speed of -w sin α. The plane's speed is v, so using Pythagorean theorem, the y component of the plane's speed is:
v² = (-w sin α)² + vᵧ²
v² = w² sin²α + vᵧ²
vᵧ = √(v² − w² sin²α)
The total vertical speed is therefore √(v² − w² sin²α) − w cos α.
If a is the length of AB, then the time is:
t = a / [√(v² − w² sin²α) − w cos α]
To rationalize the denominator, we multiply by the conjugate.
t = a / [√(v² − w² sin²α) − w cos α] × [√(v² − w² sin²α) + w cos α] / [√(v² − w² sin²α) + w cos α]
t = a [√(v² − w² sin²α) + w cos α] / (v² − w² sin²α − w² cos²α)
t = a [√(v² − w² sin²α) + w cos α] / (v² − w²)
Answer:
60 pills
Step-by-step explanation:
The <em>correct answer</em> is:
Place the point of the compass on the vertex of our original angle. Open the compass to a random width and draw an arc through both legs of the angle. Mark the points of intersection with this arc and the sides of the angle.
Explanation:
In order to copy the angle, we need to have some reference for how wide the angle is.
So far all we have is a ray. To get the reference for the width that we need, we will construct an arc in the original angle such that it intersects each side of the angle.
We will then set the compass width to these points of intersection. This will be how we set the width of the new angle.