9514 1404 393
Answer:
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
__
Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
ASA - verticals angles are equal, two sides are equal, and two other angles are marked equal
Absolute value of -2 is 2
absolute value of -3 is 3
so now the equation is 4 x 2 - 3
do 4 x 2 first = 8
now do 8 - 3 = 5
Answer:
You are given a right triangle. The sum of the two acute angles should add up to 90 degrees. Set up an equation using the expressions given and solve for x. Once you know the value of x plug it back into each expression to find the measure for each angle.
Step-by-step explanation:
Angle 1 + angle 2 = 90
solve for x = ____
Plug the value into each expression to find the measure of each angle.