So for this problem, the x-axis is the horizontal line in the center.
Go to where -2 is on the x-axis as shown. Use your finger to trace along since that's usually helpful in finding the point.
Move your finger from -2 on the x-axis to where the solid black line is. On the right side of that, you can see that the y-axis holds the number 2 which is what the y equals for this solid line.
Therefore, the answer should be c.) y = 2
Answer:
BBBBBBBBBB
Step-by-step explanation:
yeah if you add 2 without parenthesis it goes up
Answer:
(a)23 (b)90 (c)3
Step-by-step explanation:
The equation for the line of best fit for this situation is given as
where x=average temperature in degrees
y=average number of hot dogs she sold,
(a) The expected number of hot dogs sold when the temperature is 50° would be___hot dogs.
When x=50°
![y=\frac{3}{10}X50+8=15+8=23](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B10%7DX50%2B8%3D15%2B8%3D23)
When the temperature is 50°, the expected number of hot dogs sold would be 23.
(b)If the vendor sold 35 hot dogs, the temperature is expected to be ___degrees.
If y=35
![35=\frac{3}{10}x+8\\35-8=\frac{3}{10}x\\27=\frac{3}{10}x](https://tex.z-dn.net/?f=35%3D%5Cfrac%7B3%7D%7B10%7Dx%2B8%5C%5C35-8%3D%5Cfrac%7B3%7D%7B10%7Dx%5C%5C27%3D%5Cfrac%7B3%7D%7B10%7Dx)
Multiply both sides by 10/3
![27 X \frac{10}{3}= \frac{3}{10}x X \frac{10}{3}\\x=90^{0}](https://tex.z-dn.net/?f=27%20X%20%5Cfrac%7B10%7D%7B3%7D%3D%20%5Cfrac%7B3%7D%7B10%7Dx%20X%20%5Cfrac%7B10%7D%7B3%7D%5C%5Cx%3D90%5E%7B0%7D)
If the vendor sold 35 hot dogs, the temperature is expected to be 90 degrees.
(c) Based on the line of best fit, for every 10-degree increase in temperature, she should sell 3 more hot dogs.
Answer:
x=3
Step-by-step explanation:
We are given the equation
![log5x=log(2x+9)](https://tex.z-dn.net/?f=log5x%3Dlog%282x%2B9%29)
This can be rewritten as
![log5x-log(2x+9)=0](https://tex.z-dn.net/?f=log5x-log%282x%2B9%29%3D0)
Now using the quotient rule for logarithms we can combine these two
![log(\frac{5x}{2x+9} )=0](https://tex.z-dn.net/?f=log%28%5Cfrac%7B5x%7D%7B2x%2B9%7D%20%29%3D0)
Next we can remove the log by using an inverse operation
![10^{log(\frac{5x}{2x+9} )} =10^0\\\\\frac{5x}{2x+9}=1](https://tex.z-dn.net/?f=10%5E%7Blog%28%5Cfrac%7B5x%7D%7B2x%2B9%7D%20%29%7D%20%3D10%5E0%5C%5C%5C%5C%5Cfrac%7B5x%7D%7B2x%2B9%7D%3D1)
Now we can solve for x
![\frac{5x}{2x+9}=1\\\\5x=2x+9\\\\3x=9\\\\x=3](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B2x%2B9%7D%3D1%5C%5C%5C%5C5x%3D2x%2B9%5C%5C%5C%5C3x%3D9%5C%5C%5C%5Cx%3D3)
Deal with the brackets first
(2x5) = 10
Then 10 cubed = 1000
Hope this helps