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Arlecino [84]
3 years ago
12

The distance around a circle is 37.7 meters long. what is the diameter of the circle?

Mathematics
1 answer:
aksik [14]3 years ago
6 0
Ok so we know that the distance around the circle (or circumference) is equal to the diameter times pi.
This means that
37.7 = \pi \times d
d being the diameter,

This means that:
d =  \frac{37.7}{\pi}
= 12.00028271
= 12 m

So the diameter of the circle is 12 metres.

Hope this helped
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Can someone please help me with number 5? please
UNO [17]
\frac{4n^2c^5}{8nc^4}=\frac{4nc^4(nc)}{4nc^4(4)}=\frac{nc}{4}
6 0
3 years ago
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Read each problem carefully and solve as required then answer the questions that follow
zepelin [54]

Answer:

Step-by-step explanation:

1) Number of children = c

Number of adults = a

Total ticket = 250

c + a = 250 -------------------(I)

Cost of 'c' children tickets = 200c

Cost of 'a' adult tickets =  450a

Total cost = 76000

200c + 450a = 76000  ------------------(II)

Multiply (I) by (-200) and then add

(I)*(-200)          -200c - 200a = -50000

(II)                    <u> 200c + 450a = 76000 </u>

<u> </u>                                    250a = 26000

                                           a = 26000/250

a = 104

Plug in a = 104 in equation (1)

c + 104 = 250

         c = 250 - 104

        c = 146

2)Number of children = 146

Number of adults = 104

7 0
3 years ago
Find the area of shaded region.
Rudiy27

Hey there mate ;),

Area of The shades region is <u>3098 m^2</u>

The solution is attached as picture. Please check.

<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin</em>

6 0
2 years ago
Select the correct answer.<br> Which function is the inverse of ?
Artyom0805 [142]

<u>Answer:</u>

B.    f^{-1}(x) = \frac{x + 3}{9}

<u>Step-by-step explanation:</u>

let \space\ y = f(x)\\\\y = 9x -3\\

• Now make x the subject of the equation:

9x = y + 3\\\\x = \frac{y + 3}{9} \\

• Replace x with f⁻¹(x) and y with x:

f^{-1}(x) = \frac{x + 3}{9}

6 0
2 years ago
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a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

1/2 = e^{-0.137t}

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ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

3 0
3 years ago
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