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Mariana [72]
3 years ago
14

Find the common difference of the arithmetic sequence -19, -16, -13, ...

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

d= +3

Step-by-step explanation:

1st term = -19

2nd term = -16

d = 2nd - 1st

d= -16-(-19)

d = +3

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A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. (If an answer does
NNADVOKAT [17]

The question is not clear, but it is possible to obtain distance, s, from the given function. This, I would show.

Answer:

s = 17 units

Step-by-step explanation:

Given f(t) = t³ - 8t² + 27t

Differentiating f(t), we have

f'(t) = 3t² - 16 t + 27

At t = 0

f'(t) = 27

This is the required obtainaible distance, s.

6 0
3 years ago
5(-7)+9(4) I am confused on this problem
amm1812

Answer:

the answer is 1

Step-by-step explanation:

5 0
3 years ago
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Given the function, f(x)= square root 3x+3+3, choose the correct transformation(s).
ki77a [65]

Answer:

3+3+3x

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Step-by-step explanation:

3 0
3 years ago
PLEASE HELP!! Question with picture is below
Alenkinab [10]

Answer:

It honestly does not matter, but I'd choose the ring because I feel like it is more pleasant to look at.  

Step-by-step explanation:

We need to find the area of both shapes to compare:

3/4 of a circle:

A = 6^2pi

= 36pi

36pi(0.75) = 27pi

Ring:

A = 36pi

A2 = 3^2pi = 9pi

36pi-9pi = 27pi

As you can see, the two areas are the same.

Hope this helped! :)

8 0
3 years ago
Read 2 more answers
the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)
oksano4ka [1.4K]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9
6 0
3 years ago
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