Solve each equation for 0 ≤ θ 2π -2√2=-4sin 2θ
1 answer:
Answer:
Step-by-step explanation:
Begin by dividing both sides by -4 to get:
and then take the inverse sin of both sides to get
(the inverse sin undoes the sin on the right). Now we need to look on our unit circle to find the angles where is positive. There are 2 places. Sin is positive in both QI and QII. The angles are
. Therefore, our 2 equations are
and . Solving the first equation:
and the second equation:
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Answer:
Step-by-step explanation:
<u>Slope- intercept form:</u>
<u>Given</u>
m = -38 and point (0, 10)As per given point, y-intercept is b = 10
<u>So the equation is:</u>
Answer:
-5,-8,-11,-14,-17
Step-by-step explanation:
-3n -2
n=1 -3(1) -2 = -3-2 = -5
n=2 -3(2) -2 = -6-2 = -8
n=3 -3(3) -2 = -9-2 = -11
n=4 -3(4) -2 = -12-2 = -14
n=5 -3(5) -2 = -15-2 = -17
Deductive reasoning because you start from a given set of rules and conditions to determine must be true
Answer:
The answer is d the last one
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
The Domain is All Real x.
The minimum value of f(x) is -9, so:
the range is f(x) ≥ -9.