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Dmitrij [34]
3 years ago
12

Help, please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
natulia [17]3 years ago
8 0
I'm not the greatest at math, but I believe that the length of the rectangle is x-2 and the width is 2x-5. It gave you the area, which is length times width, which means that (x-2)(2x-5)=56. Then you would have to distribute and subtract 56 from both sides. Are you learning about the quadratic formula right now? Because it would have to be used here if I'm doing this right. I could be wrong!
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The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
2 years ago
1. Consider the data set 1,2,3,4,5,6,7,8,9.
ivanzaharov [21]

Answer:  a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0
3 years ago
Can someone please check this I'm not sure if it's y=126 or is the 126 negative
timurjin [86]
So to solve for y, subtract 108 from each side.
The equation becomes -y=126

Since you don't want y to be negative then divide each side by -1 this will flip all of the signs (positives become negative and vice versa) without changing the number.

So the equation is now y= -126
6 0
3 years ago
Ramandeep has a garden that is 6 and ⅔ feet by 7 and ⅘ feet. On the long side ¾ of the garden is planted and the remaining ¼ is
Ad libitum [116K]
1 2 3 4 your gonna get wrong hehehehehe
3 0
3 years ago
Read 2 more answers
Un móvil azul de 573 g se encuentra en movimiento sobre un carril metálico. Si sobre el móvil, el resorte ejerce una fuerza haci
ad-work [718]

Answer:

The total mechanical energy is 0.712 J.

Step-by-step explanation:

A blue 573 g mobile is moving on a metal rail. If on the mobile, the spring exerts a force to the right of modulus 0.85 N and in the indicated position the kinetic energy of the mobile-spring system is 0.47 J and its elastic potential energy is 0.242 J. Determine the mechanical energy of the system mobile-spring in the position shown as indicated in the figure.

The total mechanical energy is given by the sum of the kinetic energy and the potential energy.

Kinetic energy = 0.47 J

Potential energy = 0.242 J

The total mechanical energy is

T = 0.47 + 0.242 = 0.712 J

4 0
2 years ago
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