All categories

3 years ago

Which expression is equivalent to RootIndex 4 StartRoot x Superscript 10 Baseline EndRoot?

Mathematics

1 answer:

Darya [45]3 years ago

8 0

Answer:

Which expression is equal to ? The correct answer is B.

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/1312867-which-expression-is-equivalent-to-rootindex-3-startroot-64-a.html

You might be interested in

What is the value of y in the system of equations 6x-y=2 and 4x-y=-8

uysha [10]

Answer:

y=28

Step-by-step explanation:

6x-y=2

-y=2-6x

y=6x-2

4x-(6x-2)=-8

4x-6x+2=-8

-2x=-10

x=5

y=6*5-2=30-2=28

y=28

8 0

2 years ago

Please help me !!!!!!!!!!!!!!!!!!

Vitek1552 [10]

Answer:

11.27

Step-by-step explanation:

8 0

3 years ago

Complete the sequence. 1/2,3/5,5/8,7/11, ___ , ____ (will mark brainliest)

pochemuha

Answer:

1/2,3/5,5/8,7/11,9/14,11/17

Explanation:

Each time, the numerator of the fraction goes up by 2 and the denominator goes up by 3.

8 0

2 years ago

Read 2 more answers

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

Find the sum of the constants a, h, and k such that

ra1l [238]

Answer:

Step-by-step explanation:

The value of "a" is the coefficient of x^2, so we know that is 2.

Solve for h

Now, we have ...

2x^2 -8x +7 = 2(x -h)^2 +k

Expanding the right side gives us ...

= 2(x^2 -2hx +h^2) +k

= 2x^2 -4hx +2h^2 +k

Comparing x-terms, we see ...

-4hx = -8x

h = (-8x)/(-4x) = 2

Solve for k

Now, we're left with ...

2h^2 +k = 7 = 2(2^2) +k = 8 +k

Subtracting 8 we find k to be ...

k = 7 -8 = -1

And the sum of constants a, h, and k is ...

a +h +k = 2 +2 -1 = 3

The sum of the constants is 3.

6 0

3 years ago