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Juli2301 [7.4K]
3 years ago
14

Help me plz it’s due rn

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

x= 8/12 or x = 18/12

Step-by-step explanation:

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When building a house, the number of days required to build varies inversely with with the number of workers. One house was buil
masha68 [24]

Answer:

See below

Step-by-step explanation:

We can make a the number of days and y the number of workers

Since we were told there is an inverse relationship between the days required to build the house and the number of workers required, then,

The equation would be

y = k/x

Here, y is inversely proportional to x and k is the constant proportionality

So, out required equation would be

a = k/n

Fixing the values, we'll have

55 = k/8

k = 55 × 8

k = 440

The number of days required to build a similar house with 5 workers will now be

= 440/5

= 88 days

8 0
3 years ago
Area = length x width
11Alexandr11 [23.1K]
What is the length and the width you need those to answer the question
4 0
3 years ago
Using this table, calculate the profit at each level of bicycle production. One bike: -$ Two bikes: $ Three bikes: $ Four bikes:
Zielflug [23.3K]

Answer:

26

Step-by-step explanation:

6 0
4 years ago
12. Find the measure of each interior angle of triangle QRT.
Veseljchak [2.6K]

Answer:

\angle QRT=125.6\°

\angle RTQ=6.4\°

\angle TQR=48\°

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle 17x is an exterior angle of the triangle QRT. Then:

17x=\angle RTQ+\angle TQR

Where:

\angle RTQ=2x\\\\\angle TQR=48\°

Substituting values and solving for "x", we get:

17x=2x+48\\\\17x-2x=48\\\\15x=48\\\\x=3.2

Then:

17x=17(3.2)=54.4\°\\\\\\\angle RTQ=2(3.2)=6.4\°

The sum of the interior angles of a triangle is 180°, therefore:

\angle QRT+\angle RTQ+\angle TQR=180

Solving for \angle QRT, we get:

\angle QRT=180-48-6.4=125.6\°

8 0
4 years ago
What is the sum of zeros of the function y=6x^2-x-2 ?
Vsevolod [243]
y=6x^2-x-2\ \ \ \Rightarrow\ \ \ \Delta=(-1)^2-4\cdot6\cdot(-2)=1+48=49\\\\\Delta>0\ \ \ \Rightarrow\ \ \ exist\ two\ zeros\ of\ the\ function\\\\Vieta's\ formulas:\ \ \ x_1+x_2=- \frac{b}{a} \\\\x_1+x_2=- \frac{-1}{6} = \frac{1}{6}\\\\Ans.\ \ \ The\ sum\ of\ zeros\ is\   \frac{1}{6}
8 0
3 years ago
Read 2 more answers
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