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IrinaVladis [17]
3 years ago
7

Please help!! ASAP!!! Top 3 mainly

Mathematics
2 answers:
kirill [66]3 years ago
6 0

Step-by-step explanation:

Rules:

\sqrt[n]{a} = a^{\frac{1}{n}}

\sqrt[n]{a^m} = a^{\frac{m}{n}}

1.

\sqrt[3]{2} = 2^{\frac{1}{2}}

2.

\sqrt[3]{2x^2} = \sqrt[3]{2} \sqrt[3]{x^2} = 2^{\frac{1}{3}}x^{\frac{2}{3}}

3.

\sqrt[3]{(2x)^2} = \sqrt[3]{4x^2} = \sqrt[3]{4} \sqrt[3]{x^2} = 4^{\frac{1}{3}}x^{\frac{2}{3}}

defon3 years ago
5 0
7. 2^1/3
8. (2x^2)^1/3
9. 2x^2/3
11. 5_/243^6
12. _/ (1/32)^5
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Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0
2 years ago
PLEASEE HELP I ONLY HAVE 3 MINUTES LEFT PLEASE HELP ME
skelet666 [1.2K]

Answer:The graph of F is shifted 3 to the left and 1 up

Step-by-step explanation:

On the x axis, negative is left, positive is right. On the y axis, negative goes down, positive goes up. X is negative, it goes to the left, and y is positive, it moves up. Hope this helps and good luck!

6 0
3 years ago
Simplify (-2/5) divided by (8/9) times (2/9) divided by (-1/3) explain and show all steps
spayn [35]

Simplification of (-2/5) divided by (8/9) times (2/9) divided by (-1/3) is 0.3

<em><u>Solution:</u></em>

Given that,

Simplify (-2/5) divided by (8/9) times (2/9) divided by (-1/3)

Here "times" represent multiplication

<em><u>The above sentence can be written mathematically as:</u></em>

\frac{-2}{5} \div \frac{8}{9} \times \frac{2}{9} \div \frac{-1}{3}

Convert the problem to multiplication by changing the division sign to multiplication. When we change division sign to multiplication, the fraction becomes reciprocal

\rightarrow \frac{-2}{5} \times \frac{9}{8} \times \frac{2}{9} \times \frac{3}{-1}

Cancelling the common terms in numerator and denominator,

\rightarrow \frac{-2}{5} \times \frac{1}{8} \times \frac{2}{1} \times \frac{3}{-1}

Multiplying terms in numerator and denominator,

\rightarrow \frac{-12}{-40}

Negative sign in numerator and denominator cancels each other

\rightarrow \frac{-12}{-40} = \frac{12}{40}

Reducing to lowest terms we get,

\rightarrow \frac{12}{40} = \frac{3}{10}

In decimal form we get,

\rightarrow \frac{3}{10} = 0.3

Thus solution to given expression is 0.3

8 0
3 years ago
10 ounces is what fraction of a pound?
kicyunya [14]
There are 16 oz. in a pound.
10/16
5/8
7 0
3 years ago
Simplify -4 • -4 • -4
WARRIOR [948]

Answer: -64

Step-by-step explanation: Since we know that -4 x -4 is a positive, it equals 16, then a positive plus a negative equals a negative, so 16 x -4 equals <u>-64</u>

8 0
3 years ago
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