Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Answer: -1
Step-by-step explanation:
i really don't know but i was taking a test and i guessed it and it was right
Answer:
Step-by-step explanation:
The standard charge includes an initial fee and plus an addditional fee for each mile driven and is given by:
The insurance charge is given by:
So, the total charge C will be the sum of the standard charge S and the insurance charge I:
Substitute:
Rearrange:
Add:
And we have acauired our equation relating C to M!
