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3 years ago

What is the Hcf of 5, 6 and 7.

Mathematics

1 answer:

lawyer [7]3 years ago

6 0

Answer:

8.9and 10

Step-by-step explanation:

1234

567

8910

Hahaha

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You found a job that pays $15 per hour. After working for one year, you will get a 4% raise. What will be your new pay rate afte

hammer [34]

It will be 60 because you multiple 15 by 4

4 0

3 years ago

Please give a real answer! I will give brainliest!

scoundrel [369]

Answer:

{(3, 5), (2, 5), (3,8)}

Step-by-step explanation:

separate the x's & y's & put them in separate brackets

3 0

3 years ago

WHAT IS 41SQUARED PLUS XSQUARED +213?

Bingel [31]

Answer:

1894+x^2

Step-by-step explanation:

1894+x^2

41 squared IS 1,681.

Adding 213 makes it 1894.

And you end up with the expression 1894+x^2

Hope this helps!

4 0

3 years ago

In studies for a medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.

timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

$p = 0.03$

$q = 1 - 0.03 = 0.97$

The mean is

$\mu = np$

$\mu = 643 \times 0.03 = 19.29$

The standard deviation is

$\sigma = \sqrt{npq}$

$\sigma = \sqrt{643 \times 0.03 \times 0.97}$

$\sigma =4.33$

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

$P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 1.20) \\ = 0.051$

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

$P(X \: < \: 24.5) = P(z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P(z \: < \: 1.20) \\ = 0.8849$

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

$P(X \: > \: 10.5) = P(z \: > \: \frac{10.5 - 19.29}{4.33} ) \\ = P(z \: > \: - 2.03)$

$= 0.9788$

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

$P(23.5 \: < \: X \: < \: 28.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{28.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 2.13) \\ = 0.1494$

3 0

3 years ago

Suzanne bought 50 apples at the orchard she bought four times as many red apples screen. How many more red apples and green appl

RSB [31]

50 x 4 = 200

200 -50 = 150

Suzanne bought 150 more red apples

3 0

3 years ago