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vekshin1
2 years ago
7

What is the Hcf of 5, 6 and 7.

Mathematics
1 answer:
lawyer [7]2 years ago
6 0

Answer:

8.9and 10

Step-by-step explanation:

1234

567

8910

Hahaha

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Which of the following<br> represents 9!<br> A. 9<br> B. 9*8*7*6*5*4*3*2*1<br> C. 9+8+7+6+5+4+3+2+1
Zielflug [23.3K]
The answer is B. Btw don’t click on the link provided by the other answer provider it’s a virus.
3 0
2 years ago
Pls ans.thanks a lot
yawa3891 [41]

Answer:

you're answer is -2

Step-by-step explanation:

i hope this helped you have a nice day  :)

6 0
2 years ago
George collects 25 baseball cards each month. How many cards will he have at the end of one year? Complete the equation to help
kaheart [24]
25(cards per month) x12(months in one year) =300 cards at the end of one whole year
4 0
3 years ago
Read 2 more answers
Marion bought 14 packages of plastic frog and lizard fishing lures. She bought frog lures in packages of 4 and lizard lures in p
tatuchka [14]

Answer:

Marion bought 6  frog lures and 8 lizard fishing lures.

Step-by-step explanation:

Let f represent frog lures and l represent lizard lures.


The total packages Marion bought is

f+l=14...eqn1


If she bought frog lures in packages of 4 and lizard lures in packages of 6 for a total of 72 lures, then

4f+6l=72...eqn2


We make f the subject in equation 1 and put it into equation 2 to get;

f=14-l...eqn3


We put equation 3 into equation 2 to get;

4(14-l)+6l=72


\Righttarrow 2(14-l)+3l=36


We expand the bracket to get;

28-2l+3l=36


-2l+3l=36-28


l=8


We put l=8 into equation 3 to get;

f=14-8


f=6

Therefore Marion bought 6  frog lures and 8 lizard fishing lures.


6 0
2 years ago
1. Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial i
Katena32 [7]
Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be  2 - 5i and:

f(x)=\big(x-4\big)\big(x-(-8)\big)\big(x-(2+5i)\big)\big(x-(2-5i)\big)=\\\\=(x-4)(x+8)(x-2-5i)(x-2+5i)=\\\\=(x^2-4x+8x-32)(x^2-2x+5ix-2x+4-10i-5ix+10i-25i^2)\\\\=\big(x^2+4x-32\big)\big(x^2-4x+4-25\cdot(-1)\big)=\\\\=(x^2+4x-32)(x^2-4x+29)=\\\\=x^4-4x^3+29x^2+4x^3-16x^2+116x-32x^2+128x-928=\\\\=\boxed{x^4-19x^2+244x-928}

Answer B.
8 0
3 years ago
Read 2 more answers
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