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3 years ago

Please helppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Masteriza [31]3 years ago

3 0

The unit rate would be 11/2. Hope this helped.

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Write the following ratios in its simplest form 56:112:28

damaskus [11]

Answer:

2 : 4 : 1

Step-by-step explanation:

First take common factors by factorization.

56 = 14 x 4 = 28 x 2

112 = 14 x 8 = 28 x 4

28 = 14 x 2 = 28 x 1

Remove the 28 common factor.

Therefore,

56 : 112 : 28

= 2 : 4 : 1

5 0

3 years ago

A lighthouse that is 36 ft tall stands on the shore of lake michigan. Looking out from atop the lighthouse, a ship suddenly appe

UNO [17]

The distance (in miles) viewable to horizon of a lighthouse oh height h (in feet) is given by approximately

$\sqrt{ \frac{7h}{4} }$

Given that a lighthouse that is 36 ft tall stands on the shore of Lake Michigan, the distance of the boat it can see on the horizon is given by approximately

 $\sqrt{ \frac{7\times36}{4} } = \sqrt{63} \approx7.94$

4 0

3 years ago

Radioactive Decay

SpyIntel [72]

Answer:

Percentage of (226Ra) after 900 years is 68%

Step-by-step explanation:

Let P(t) be the amount of (226Ra) present at any time t

Half life of (226 Ra) = 1599 years

If P₀ is initial amount of (226 Ra) then after 1599 years

P(1599)=P₀/2

Decay i amount of radioactive substance is related to time t as

$\frac{dP}{dt}=kP(t)\\\\\frac{1}{P}\,dP=kdt\\\\Integrating\,\, both\,\,sides\\\\ln|P|=kt+c\\\\P(t)=Ce^{kt}\\\\at \,\, t=0\,\, P(0)=P_{o}\\\\P(0)=Ce^{k0}\\\\P_{o}=C\\\\then\\\\P(t)=P_{o}e^{kt}$

To find value of k

$at\,\, t=1599\,years\\\\P(1599)=\frac{P_{o}}{2}\\\\then\\\\\frac{P_{o}}{2} =P_{o}e^{k(1599)}\\\\\frac{1}{2} =e^{k(1599)}\\\\ln|\frac{1}{2}|=k(1599)\\\\k=\frac{ln|\frac{1}{2}|}{1599}=-4.3\times 10^{-3}\\\\\implies P(t)=P_{o}e^{-4.3\times 10^{-3}t}\\\\at\,\, t=900 \\\\P(900)=P_{o}e^{-4.3\times 10^{-3}(900)}\\\\P(900)=0.68P_{o}$

Percentage of radioactive element is:

Amount after 900 years $=\frac{P(900)}{P_{o}}\times 100\\\\=\frac{0.68P_{o}}{P_{o}}\times 100\%\\\\=68\%$

3 0

3 years ago

Consider the sequence below. If we represent this sequence with the letter a then do the following

slamgirl [31]

Answer:

a(5)=25

a2+a6=44

a(4)+2a(6)=93

sqrta(5)=5

Step-by-step explanation:

You are given all the terms needed but sometimes you will have to create a formula.

a(b)=6b-5 is the formula in this sequence, now you can just plug in everything.

a(5)=6(5)-5

=25

a2=7

a6=37

7+37=44

a(4)=19, a(6)=37

19+2(37)=93

a(5)=25

sqrt25=5

5 0

3 years ago

Please can someone answer this question quickly please Thanks

inessss [21]

Answer:

C. 5/7

Step-by-step explanation:

8 0

3 years ago

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