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Alexxandr [17]
3 years ago
9

1) Tommy mows lawns and cleans pools during the summer. He earns $20 per lawn and $9 per

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

Step-by-step explanation:

20L+9P\ge 1500,\ L=41\\ \\ 20(41)+9P\ge 1500\\ \\ 820+9P\ge 1500\\ \\ 9P\ge 680\\ \\ P\ge 75.6\\ \\ P=76

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A bird is flying 33 feet above sea level, a diver is 20 feet below sea level. What
iren [92.7K]

Answer:

53 feet

Step-by-step explanation:

If the bird is flying 33 feet above sea level, and the diver is 20 feet below it would be 53 because you have to imagine right at sea level is a zero and 20 below with 33 above would equal 53

4 0
4 years ago
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Over the past several years, the proportion of one-person households has been increasing. The Census Bureau would like to test t
bixtya [17]

Answer:

For this case we can find the critical value with the significance level \alpha=0.05 and if we find in the right tail of the z distribution we got:

z_{\alpha}= 1.64

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:  

z=\frac{0.344 -0.27}{\sqrt{\frac{0.27(1-0.27)}{125}}}=1.86  

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of households with one person is significantly higher than 0.27

Step-by-step explanation:

We have the following dataset given:

X= 43 represent the households consisted of one person

n= 125 represent the sample size

\hat p= \frac{43}{125}= 0.344 estimated proportion of  households consisted of one person

We want to test the following hypothesis:

Null hypothesis: p \leq 0.27

Alternative hypothesis: p>0.27

And for this case we can find the critical value with the significance level \alpha=0.05 and if we find in the right tail of the z distribution we got:

z_{\alpha}= 1.64

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:  

z=\frac{0.344 -0.27}{\sqrt{\frac{0.27(1-0.27)}{125}}}=1.86  

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of households with one person is significantly higher than 0.27

5 0
3 years ago
Who swims faster Sarah or Eva? WILL NAME BRAINIEST
Greeley [361]

Answer:

Eva swims faster than Sarah

Step-by-step explanation:

At first, they swim at different rates, but if you compare the last two (17/425 and 20/520) Eva swam the fastest.

4 0
3 years ago
Read 2 more answers
Make a two-column proof showing statements and reasons to prove that triangle DEF is similar to triangle DGE. (10 points)
spayn [35]
I dont understand that I can’t see the picture that good
4 0
3 years ago
In the data set below, what is the mean absolute deviation? 3 8 6 9 2 5
zepelin [54]
<h3>Answer:  Approximately 2.1667</h3>

==========================================================

Explanation:

First we need to find the arithmetic mean.

Add up the values to get 3+8+6+9+2+5 = 33

Divide this over 6 because there are 6 values: 33/6 = 5.5

The mean is 5.5

------

Subtract the mean from each data value. Apply absolute value to ensure the result is not negative.

  • |3 - 5.5| = |-2.5| = 2.5
  • |8 - 5.5| = |2.5| = 2.5
  • |6 - 5.5| = |0.5| = 0.5
  • |9 - 5.5| = |3.5| = 3.5
  • |2 - 5.5| = |-3.5| = 3.5
  • |5 - 5.5| = |-0.5| = 0.5

Each result represents how far that specific data value is from the mean. Absolute value is used to find distance on a number line.

Add up each of those results to get: 2.5+2.5+0.5+3.5+3.5+0.5 = 13

Then divide by 6 to find the average: 13/6 = 2.1667 which is approximate

The mean absolute deviation represents the average distance any given value is from the mean. The term "deviation" refers to how far each data value is from the mean, which is the center point we're after more or less.

The MAD (mean absolute deviation) effectively measures how spread out the data set is. The larger the MAD, the more spread out the data is likely to be. The range, standard deviation and variance are also measures of spread.

6 0
3 years ago
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