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2 years ago

12dollers for 3 staeks 28 for 7staeks

Mathematics

1 answer:

Lyrx [107]2 years ago

8 0

The unit rate would be:
4 dollars for 1 steak

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The value of the 4 in 34,258 and 47,163

Lera25 [3.4K]

The value of 4 in 34,258 is 10 times the value of the 4 in 47,163.

7 0

3 years ago

I just need help at this point.

Greeley [361]

Answer:

Step-by-step explanation:you take the 740 and divide it by 40 to get the hourly wage then times that by the 32 and theirs your answer

4 0

3 years ago

Read 2 more answers

2 1/3 −1.5x=12.3 please help me I'm really struggling need an answer ASAP.

Harrizon [31]

Answer:

-6.64

Step-by-step explanation:

since you need to find the value of x , but all values to one side and have x on the other .. meaning :

2 1/3 -12.3 = 1.5x

now that you have this find the decimal value of 2 1/3

which is 2*3 +1 = 7/3

in decimal form is 2.33333...

now subtract (2.3333.. - 12.3 ) / 1.5

x = -6.6444

to 3 sf = -6.64

7 0

2 years ago

Find the value of x. A. 35 B. 10 C. 55 D. 25

dolphi86 [110]

Answer:

A.35

Step-by-step explanation:

trust bro

5 0

2 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago