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iren2701 [21]
2 years ago
13

HELPP PLEASEEEEEEE

Mathematics
1 answer:
Alexxx [7]2 years ago
7 0
A, c, and d
plug in each x in the equation and it should equal the y value
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What is the equation for an explicit formula
umka21 [38]
It defines the sequence as a formula<span> in terms of n. ... Sequence: {10, 15, 20, 25, 30, 35, ...}. Find an </span>explicit formula<span>. This example is an arithmetic sequence(the same number, 5, is added to each term to get to the next term).</span>
5 0
3 years ago
Simplify (3x - 5) - (5x + 1).<br> 0-2x + 6<br> -2x - 6<br> 2x - 6<br> 2x + 6<br> fast please!
mamaluj [8]
-2x-6

EXPLANATION

(3x-5) = (-2x) - 6
3 0
3 years ago
Given: ABC is a right triangle with right angle C. AC=15 centimeters and m∠A=40∘ . What is BC ? Enter your answer, rounded to th
konstantin123 [22]

In order to answer this question, the figure in the first picture will be helpful to understand what a right triangle is. Here, a right angle refers to 90\°.


However, if we want to solve the problem we have to know certain things before:


In the second figure is shown a general right triangle with its three sides and another given angle, we will name it \alpha:


  • The side <u>opposite to the right angle</u> is called The Hypotenuse (h)
  • The side <u>opposite to the angle \alpha</u> is called the Opposite (O)
  • The side <u>next to the angle \alpha</u> is called the Adjacent (A)

So, going back to the triangle of our question (first figure):


  • The Hypotenuse is AB
  • The Opposite is BC
  • The Adjacent is AC

Now, if we want to find the length of each side of a right triangle, we have to use the <u>Pythagorean Theorem</u> and T<u>rigonometric Functions:</u>


Pythagorean Theorem


h^{2}=A^{2} +O^{2}    (1)  


Trigonometric Functions (here are shown three of them):


Sine: sin(\alpha)=\frac{O}{h}    (2)


Cosine: cos(\alpha)=\frac{A}{h}    (3)


Tangent: tan(\alpha)=\frac{O}{A}   (4)



In this case the function that works for this problem is cosine (3), let’s apply it here:


cos(40\°)=\frac{AC}{h}    


cos(40\°)=\frac{15}{h}    (5)


And we will use the Pythagorean Theorem to find the hypotenuse, as well:



h^{2}=AC^{2}+BC^{2}    


h^{2}=15^{2}+BC^{2}    (6)


h=\sqrt{225+BC^2}   (7)



Substitute (7) in (5):


cos(40\°)=\frac{15}{\sqrt{225+BC^2}}    


Then clear BC, which is the side we want:


{\sqrt{225+BC^2}}=\frac{15}{cos(40\°)}


{{\sqrt{225+BC^2}}^2={(\frac{15}{cos(40\°)})}^2


225+BC^{2}=\frac{225}{{(cos(40\°))}^2}


BC^2=\frac{225}{{(cos(40\°))}^2}-225


BC=\sqrt{158,41}


BC=12.58


Finally BC is approximately 13 cm



7 0
3 years ago
Read 2 more answers
Which of the following shows a number in fraction form? A. 3 B. 3.7 C. 3 ∕7 D. √2
kumpel [21]
C because u have 3/7 which is a fraction
7 0
3 years ago
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In the himalaya mountains allong the border of tibet and nepal mount everest reaches a record height of 29,035 feet. How high is
Ludmilka [50]

Answer:

Step-by-step explanation:

In miles it is 29,035 / 5280

= 5.5 miles.

In kilometers it is 5.5 / 0.621 kilometres

= 8.857 km.

= 8857 m.

4 0
2 years ago
Read 2 more answers
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