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Bad White [126]
2 years ago
8

PLZ HELP ME Solve -2z – 5 > 3 for z.

Mathematics
1 answer:
Evgen [1.6K]2 years ago
7 0

Answer:

z<-4

Step-by-step explanation:

-2z-5>3

Add 5 to both sides.

-2z>8

Divide both sides by -2.

Z<-4

The sign must change because you are dividing by a negative.

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the sum of two numbers is 57. if the larger of the two numbers is 9 less than twice the smaller, find the two numbers
svp [43]

Answer:

The answer is 35 and 22

Because:

U let the numbers(#) be x and y (x will be the larger number and y the smaller number

So:

x + y =57

x = 2*y - 9

Therefore,

{2*y - 9} + y = 57

Leaving the two numbers 35 and 22

I hope I could help




7 0
3 years ago
Solve for b: 2(b + 3) = b – 4
Reil [10]

Answer:

b = -10

Step-by-step explanation:

2(b + 3) = b – 4

2b + 6 = b - 4

-b             -b

b + 6 = -4

     -6    -6

b = -10

8 0
3 years ago
Read 2 more answers
15/16 simplify lcd.
soldi70 [24.7K]

I think the answer you are looking for is 1

<u><em>NOT AT ALL 100% SURE :(</em></u>

4 0
3 years ago
Blaine buys 2 books and the total cost is $24.18. What is the constant of proportionality that relates the cost in dollars, y, t
cestrela7 [59]

Answer:

$ 12.09

Step-by-step explanation:

formula Y = KX

Where; y = $ 24.18

            x = 2 books

            k = constant of proportionality

Step 1. Do the equation based on the formula

Y = kx

$24.18 = k2

Step 2.  Divide by 2

$24.18/2 = k2/2

k = $12.09 (answer)

5 0
3 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
2 years ago
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