Let p = number of pennies.
Let n = number of nickels.
We are given that n= 2p and the total value is $8.80.
We know that a penny = $0.01 and that a nickel = $0.05.
So $0.01p + $0.05n = $8.80.
Substitute 2p for n:
$0.01p + $0.05*2p = $8.80
$0.01p + $0.10p = $8.80
$0.11p = $8.80
p = 80
So n = 2p = 2*80 = 160
Thus there are 80 pennies ($0.8) and 160 nickels ($8.00). The value of all the coins is $8.80.
Answer:
The degrees of freedom are given by:
The p value for this case would be given by:
Step-by-step explanation:
Information given
represent the mean height for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
t would represent the statistic
represent the p value for the test
Hypothesis to verify
We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Replacing the info given we got:
The degrees of freedom are given by:
The p value for this case would be given by:
Answer:
The maximum value of the equation is 1 less than the maximum value of the graph
Step-by-step explanation:
We have the equation
.
We can know that this graph will have a maximum value as this is a negative parabola.
In order to find the maximum value, we can use the equation 
In our given equation:
a=-1
b=4
c=-8
Now we can plug in these values to the equation

Now we can plug the x value where the maximum occurs to find the max value of the equation

This means that the maximum of this equation is -4.
The maximum of the graph is shown to be -3
This means that the maximum value of the equation is 1 less than the maximum value of the graph