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Korvikt [17]
3 years ago
6

9)

Mathematics
2 answers:
FromTheMoon [43]3 years ago
7 0

Answer:

It would be A

Step-by-step explanation:

<u>The Key Skill is: Distribution Property </u>

1) We have the expression 4(6-2x)

2) We have to use distribution property to expand this.

The way distribution property works is that we need to multiply the 6 by the 4 on the outside, and also the -2x by the 4 on the outside.

4 x 6 = 24

4 x -2x = -8x

Therefore, the final expression is 24-8x.  

The only answer that matches this is A.

Hope you understood & have a nice DAY!! :D

madreJ [45]3 years ago
3 0

Answer:

the answer is A.

Step-by-step explanation:

to get the you would use the distributive property to multiple the 4 by the two term in the parentheses.

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A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres
topjm [15]

Let U(t) denote the amount of uranium-238 in the reactor at time t. As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

\dfrac{\mathrm dU}{\mathrm dt}=-kU

where k>0 is constant. Separating variables and integrating both sides gives

\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}

Suppose we start some amount u. This means that at time t=0 we have U(0)=u, so that

u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if t is taken to be in years) for some starting amount u,

0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}

The half-life is the time t_{1/2} it takes for the starting amount u to decay to half, 0.5u:

0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0
3 years ago
You have to spend money to make money ! You purchase a mix of newspaper ads and online ads. Each newspaper ad cost $18.50 and ea
SpyIntel [72]

Answer:

You buy six newspaper ads & eighteen social media ads.

Step-by-step explanation:

First, we change ads into variables to be more easier to calculate :

Let newspaper = x

Let social media = y

Second, make this variables into an equation, given that you purchase a total of 24 ads :

x + y = 24 (first equation)

Next, given that x = $18.50 & y = $26.50 & spent a total of $588 so you can make another equation :

18.50x + 26.50y = 588 (second equation)

Now, solve this simultaneous equation using elimination or substitution (depends on you) :

substitution =>

x + y = 24 ----------(1)

18.50x + 26.50y = 588 ---------(2)

(1)=> y = 24 - x ------(3)

(3)=>(2) 18.5x + 26.5(24-x) = 588

18.5x + 636 - 26.5x = 588

-8x = -48

x = 6

sub x=6 into(3)

(3)=> y = 24 - 6

= 18

newspaper = x

= 6

social media = y

= 18

6 0
3 years ago
In CAT entrance examination paper there are 3 sections, each containing 5 questions. A candidate has to solve 5,
mamaluj [8]
The best and most correct answer providedfrom your question about the entrance examination paper is the second option which is 2,250. The problem can be solved by:

3-1-1 : 5c3*5c1*5c1 *3!/2! = 750 
<span>2-2-1 : 5c2*5c2*5c1 *3!/2! = 1500
</span>
Adding the two answers:

750 + 1500 = 2250

I hope it has come to your help.


4 0
3 years ago
May someone help me find A H AND K ?
NNADVOKAT [17]

Answer:

a = -2

h = -1

k = -6

Step-by-step explanation:

This is called the vertex form of a quadratic:

y = a(x – h)2 + k

To arrive at the answer, simply locate where each variable would be in place of the number.

I hope this helped you! If it did, please consider rating, pressing thanks, and marking my answer as Brainliest. It would be a big help! Have a great day! :)

7 0
3 years ago
Help help help AAAAAAA math is hard
yuradex [85]

Answer: I believe it is h

Step-by-step explanation:

8 0
3 years ago
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