X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
Answer:
C)28in
Step-by-step explanation:
To get the area of this face, we will divide it into 3 sections.
Area of the 1st section:
Given:
l=4in
w=2in
Formula:
a=l*w
Solution:
a=l*w
a=8in^2
Area of the 2nd section:
Given:
l=2in
w=2in
Formula:
a=l*w
Solution:
a=l*w
a=2in*2in
a=4in^2
Area of the 3rd section:
l=8in
w=2in
Formula:
a=l*w
Solution:
a=l*w
a=8in*2in
a=16in^2
a1+a2+a3=Area of the face
8in^2+4in^2+16in^2=28in^2
Hope this helps ;) ❤❤❤
Answer:60
Step-by-step explanation:
If the x-axis ordered pair is (0,0) and the y-axis ordered pair is (0,0), it is just where the lines intersect or also known as the origin. Both x and y can have a (0) in it.
for example let's say that you have an ordered pair on the X-axis of (5,0) and a ordered pair on the y-axis of (-3,0) it would look like that^^
or if it was just (0,0) it would be a dot in the middle
Don't know if it helped much, but there ya go