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Nat2105 [25]
3 years ago
12

Matthew made slightly larger blanket that was 8 Ft long. Its area is 64 sq ft what is its perimeter?

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

32 ft

Step-by-step explanation:

Given data

Length= 8ft

Area= 64 f^2

Let us find the width

Area= Length*Width

64= 8* Width

Width= 64/8

Width= 8ft

Hence the perimeter= 2L+2W

P= 2*8+2*8

P= 16+16

P= 32 ft

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The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

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3 years ago
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I don’t understand the question so I answer in two ways

4 0
2 years ago
WILL GIVE BRAINLIEST FOR CORRECT ANSWER
hammer [34]
Tan(35)=x/12
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6 0
3 years ago
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the area of a rectangular window is 6216 cm^2. if the length of the window is 84 cm, what is it's width?​
Rus_ich [418]

Answer:

<h3>The answer is 74 cm</h3>

Step-by-step explanation:

The area of a rectangle = length × width

Since we are finding the width

We have

width  = \frac{area}{length}  \\

From the question

area = 6216 cm²

length = 84 cm

The width is

width =  \frac{6216}{84}  \\

We have the final answer as

<h3>74 cm</h3>

Hope this helps you

3 0
3 years ago
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
3 years ago
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