What does it mean if the x-coordinate in an ordered pair is zero? What if the y-coordinate is zero? Both? Explain.

Mathematics

1 answer:

Harman [31]3 years ago

5 0

If the x-axis ordered pair is (0,0) and the y-axis ordered pair is (0,0), it is just where the lines intersect or also known as the origin. Both x and y can have a (0) in it.

for example let's say that you have an ordered pair on the X-axis of (5,0) and a ordered pair on the y-axis of (-3,0) it would look like that^^

or if it was just (0,0) it would be a dot in the middle

Don't know if it helped much, but there ya go

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Ashley mixes two types of soft drinks with different types of concentration: one soft drink has 20% sugar and the other drink ha

ICE Princess25 [194]

Answer:

Sugar concentration of the mixed soft drink will be 32.5%.

Step-by-step explanation:

Sugar concentration of first drink = 20%

Volume of first soda = 250 ml

Sugar in first soda = 20% of 250 ...... (1)

Sugar concentration of second drink = 45%

Volume of second soda = 250 ml

Sugar in second soda = 45% of 250 ...... (2)

Let $x\%$ be the sugar concentration in resultant mixture.

Volume of mixture = 250 + 250 = 500 ml

Sugar in mixture = $x\%$ of 500 ml ...... (3)

Total sugar concentration (Adding (1) and (2)) and equating it to equation (3):

20% of 250 + 45% of 250 = $x\%$ of 500

$\Rightarrow \dfrac{20}{100} \times 250 + \dfrac{45}{100} \times 250 = \dfrac{x}{100} \times 500\\\Rightarrow 2 \times x = 65\\\Rightarrow x = 32.5\%$

Hence, Sugar concentration of the mixed soft drink will be 32.5%.

8 0

3 years ago

The ratio of the volume of soda in glass A to the volume of glass B is 8/3 to 7/2

MrRa [10]

Answer:

Total volume in the two glasses is 740 mL.

Step-by-step explanation:

Given:

Ratio of the volume of soda in glass A to the volume of glass B = 8/3 : 7/2

Volume of soda in glass A = 320mL

To Find :

The total volume in the two glasses = ?

Solution:

Let the volume of soda in glass B be x

then

$\text{ratio of soda in glass A} \times \text{ the volume of soda in glass B} = \text{ratio of soda in glass B} \times \text{ the volume of soda in glass A}$