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Fantom [35]
1 year ago
8

Find m2ABC. Ad 37° 21° B m/ABC = C

Mathematics
2 answers:
grin007 [14]1 year ago
5 0
\bold{ANSWER:}
58

\bold{EXPLANATIONS:}

lidiya [134]1 year ago
3 0

Answer:

it might be 58 , just look it up I don't really know

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Find the original price of a pair of shoes if the sale price is $144 after a 25% discount.
k0ka [10]

Answer:

$192

Step-by-step explanation:

1: Subtract the discount from 100% then divide the sale price by this number (100%-25%=75%, $144/75%=$192)

hope this helped

4 0
3 years ago
Read 2 more answers
I need help with this problem PLEASE HELP
xxTIMURxx [149]

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

<h3>How to Determine the Range and the Domain of a Function?</h3>

In any given graph that represents a function, the possible set of domain values are plotted on the x-axis (horizontal axis), while the possible set of corresponding range values are plotted on the y-axis (vertical axis).

Thus, the set of x-values (input values) on a graph is the domain of the function while the set of y-values (output values) is the range of the function.

In the given graph, the set of x-values are: -5, -3, -1, and 1.

The set of y-values are: -5, -3, -1, and 1.

Therefore:

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

Learn more about the domain and range of a function on:

brainly.com/question/10197594

#SPJ1

7 0
1 year ago
Question 2 -of 15 Step 1 of 1No Time LimitA company manufactures two products. One requires 5 hours of labor, 3 poundsof raw mat
elena-14-01-66 [18.8K]

the cost of labour per hour is $7.20

the cost of raw materials per pound is $11.60

Explanation:

For product one:

time = 5 hours of labour

let the cost labour per hour = x

Amount = 3 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $70.8

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

5(x) + 3(y) = 70.80

5x+3y=70.8....\mleft(1\mright)

For product 2:

time = 3.5 hours of labour

let the cost of labour per hour = x

Amount = 13 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $176.00

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

3.5(x) + 13(y) = 176

3.5x+13y=176\text{   .... (2)}

combining both equations:

5x + 3y = 70.8 ...(1)

3.5x + 13y = 176 ....(2)

Using elimination method:

To eliminate y, we will multiply equation (1) by 13 and equation (2) by 3 so that both coefficient of y become the same

65x + 39y = 920.4 ...(*1)

10.5x + 39y = 528 ...(2*)

subtract equation (2*) from (1*):

65x - 10.5x + 39y - 39y = 920.4 - 528

54.5x + 0 = 392.4

54.5x = 392.4

divide both sides by 54.5:

x = 392.4/54.5

x = 7.2

substitute for x in any of the equations

Using equation 1: 5x + 3y = 70.8

\begin{gathered} 5\mleft(7.2\mright)+3y=\text{ 70.8} \\ 36\text{ + 3y = 70.8} \\ 3y\text{ = 70.8 - 36} \\ 3y\text{ = 34.8} \\  \\ \text{divide both sides by 3:} \\ \frac{3y}{3}=\frac{34.8}{3} \\ y\text{ = }11.6 \end{gathered}

Hence, the cost of labour per hour is $7.20 and the cost of raw materials per pound is $11.60

6 0
1 year ago
PleAse help with this question
Black_prince [1.1K]

5 it 5 it 5 555555

Step-by-step explanation:

hope this helped

8 0
2 years ago
To maintain essential electricity, a gasoline generator at a Puerto Rico hospital uses 3 gallons of gasoline per hour. a) How ma
stira [4]

The mass of the CO2 produced IS 630 Kg

<h3>What is gasoline?</h3>

Gasoline is a kind of fuel that is composed mostly of isooctane. In most engines, gasoline is widely used hence the demand for the product is high. We know that the combustion of an alkane (of which gasoline is one) would produce carbon dioxide and water according to a balanced reaction equation.

The balanced reaction equation for the combustion of gasoline is shown in the image attached to this answer.

Since  a Puerto Rico hospital uses 3 gallons of gasoline per hour, and there are 24 hours in a day, it the follows that 72 gallons of gasoline are used per day. This 72 gallons is the equivalent of 272.88 L

Now;

Given that the density of gasoline = 748.9 g/L

Mass of gasoline = 748.9 g/L * 272.88 L = 204 Kg

Number of moles of gasoline =  204 * 10^3/114 g/mol = 1789.5 moles

If 2 moles of gasoline produces 16 moles of CO2

1789.5 moles produces  1789.5 moles * 16 moles/2 moles = 14316 moles

Mass of CO2 =  14316 moles * 44 g/mol = 630 Kg

Learn more about gasoline:brainly.com/question/13402652?

#SPJ1

4 0
1 year ago
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