The table shows the outputs, y, for different inputs, x:
2 answers:
Hi there!
Let me explain each part to you, along with the answer.
a. Yes, the data represent a function. The definition of a function is a relation in which no value of x will have two different values of y. None of the numbers in the table repeat, so we can safely say that the relation is a function.
b. We are given the function
. What we are asking to find is which table has a greater output value when x = 3. To start off, we can plug in 3 into the given function.
The output value for the function is 20. When we look at the table's output value for 3, we get 6. Therefore, has a greater value when x = 3.
c. We are asked to find the output value of the function when f(x) is equal to 76. Notice that the problem did not state an x value, but instead a substitution scenario. Hence, we will need to replace f(x) with 76.
Therefore, the value of x when f(x) is equal to 76 is 17.
Hope my answer has come of assistance to you and have a magnificent day!
Let me explain each part to you, along with the answer.
a. Yes, the data represent a function. The definition of a function is a relation in which no value of x will have two different values of y. None of the numbers in the table repeat, so we can safely say that the relation is a function.
b. We are given the function
The output value for the function
c. We are asked to find the output value of the function
Therefore, the value of x when f(x) is equal to 76 is 17.
Hope my answer has come of assistance to you and have a magnificent day!
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Answer:
We conclude that 50.
Step-by-step explanation:
We are given that x bar = 60, s = 12, n = 30, and alpha = 0.10
Also, Null Hypothesis, :
= 50
Alternate Hypothesis, :
50
The test statistics we will use here is;
T.S. = ~
where, X bar = sample mean = 60
s = sample standard deviation = 12
n = sample size = 30
So, Test statistics = ~
= 4.564
At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.
P-value is given by, P( > 4.564) = less than 0.05% {using t table}
Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.
Therefore, we conclude that 50.